LBS171F06ReviewAnswers

LBS171F06ReviewAnswers - LBS 171 REVIEW QUESTIONS ANSWER...

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Unformatted text preview: LBS 171 REVIEW QUESTIONS ANSWER GUIDE MOLAR MASS 1.) a.) Na 22.9898 g/mol b.) H 2 2*1.0079 = 2.0158 g/mol c.) NH 4 14.0067 + 4*1.0079 = 18.0383 g/mol d.) C 3 H 6 Cl 2 3*12.011 + 6*1.0079 + 2*35.4527 = 112.9858 g/mol MOLARITY 2.) a.) 3.62 mol NaCl / 0.4000 L solution = 9.05 M b.) 0.36 g Na 3 PO 4 12H 2 O * (1 mol / 380.1232 g) / 0.2000 L = 4.7*10-3 M c.) (0.5 M HCl * 0.0200 L) / (0.0200 L + 0.1300 L) = 7*10-2 M STOICHIOMETRY 3.) 6.0 mol AlCl 3 * (1 mol Al(OH) 3 / 1 mol AlCl 3 ) * (133.3396 g / 1 mol Al(OH) 3 ) = 8.0*10 2 g Al(OH) 3 4.) Balanced: C 6 H 8 + 8O 2 6CO 2 + 4H 2 O 27.4 g C 6 H 8 * (1 mol C 6 H 8 / 80.1292 g) * (6 mol CO 2 / 1 mol C 6 H 8 ) * (44.0098 g / mol CO 2 ) = 90.3 g CO 2 87.6 g CO 2 / 90.3 g = 97.0 % yield 5.) Balanced: AlCl 3 + 3NaOH(aq) Al(OH) 3 + 3NaCl 4.2 M NaOH * 0.1200 L * (1 mol AlCl 3 / 3 mol NaOH) = 0.168 mol AlCl 3 LIMITING REACTANT 6.) 32.6 g Cr * (1 mol Cr / 51.9961 g) * (2 mol CrCl 3 / 2 mol Cr) = 0.627 mol CrCl 3 56.0 g Cl 3 * (1 mol Cl 3 / 106.3581 g) * (2 mol CrCl 3 / 3 mol Cl 2 ) = 0.351 mol CrCl 3 0.351 mol CrCl 3 * (158.3542 g / 1 mol CrCl 3 ) = 55.6 g CrCl 3 produced (0.627 mol CrCl 3 0.351 mol) * (2 mol Cr / 2 mol CrCl 3 ) * (51.9961 g / 1 mol Cr) = 15.9 g Cr left 7.) Balanced: 2SO 2 (g) + 2CaCO 3 (s) + O 2 (g) 2CaSO 4 (s) + 2CO 2 (g) 13.4 g CaCO 3 * (1 mol CaCO 3 / 100.0872 g) * (2 mol CaSO 4 / 2 mol CaCO 3 ) = 0.134 mol CaSO 4 15.0 L O 2 (g) * 1.429 g/L * (1 mol O 2 / 31.9988 g) * (2 mol CaSO 4 / 1 mol O 2 ) = 1.34 mol CaSO 4 10.0 L SO 2 (g) * 2.551 g/L * (1 mol SO 2 / 64.0648 g) * (2 mol CaSO 4 / 2 mol SO...
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LBS171F06ReviewAnswers - LBS 171 REVIEW QUESTIONS ANSWER...

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