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# ch7p12 - 7.26 Determine the reaction forces and the...

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Unformatted text preview: 7.26 Determine the reaction forces, and the internal forces and moments. Plot the shear and bending moment function versus the distance I. 500 Mm 100 Wm B O 5 m FIGURE P726 Solution: Following the solution of problem 4.53, the equivalent force is 1500 N applied at 3.06 m from 0. The free-body diagram for the reaction forces is illustrated. 1500 R 3135 __. 5m——— A, 3, FIGURE 57.263 2F=0:Ay+By—1500=0 2 MA = 0 : 53, — (3.06)(1500) = o By = 916.67 N, A,, = 533.33 Next consider a cut at a: and a free body of the section between A and 3. Note only one section needs to be analyzed because the load does not change abruptly any where. From the solution to 4.53: 561 = 23/3 and from similar triangles h = 801: and 1 1 P1 = §(base) (height) = —2-(:c)(80:r) = 40332. 717 ...
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