Unformatted text preview: 7.5 A bar is ﬁxed at one end and is loaded as illustrated. Ignoring the
weight of the ba.r1 compute the internal force and moment at the points
A and B. ”"4 FIGURE P7.5 Solution: Make a free body diagram of the bar cut at point A to the
free end, avoiding the boundary conditions. FIGURE $7.58 I~—~o.15rn——L
a M C '2‘!)
was) FIGURE 87.5b Froma:
2Fy=02 —V+750=0 01'
V(0.3) = 750 N 2M0 : M(.3) — (750)(o.4) = o 01' ms) = §_OO_N_I_n 676 ...
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- Summer '08