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ch7p10 - 416.67 FIGURE 37.24b and the equivalent point load...

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Unformatted text preview: 416.67 FIGURE 37.24b and the equivalent point load at 2 3‘” is 503:2 N as shown. Summing forces yields 416.67 — 50cc2 — V(a;) = 0 01‘ V(:t:) = 416.67 — 503:2 N. Summing moments about. A yields 1 3 ‘ —m(416.67 — 503:2) — 03x + M(:c) = 0 or 100 3 0 M (x) = 416.671: - 503:3 + Z = 416.672 — 531:3 Nm. Note dM/da: = V(a:). The plots are given in the computer solution section and sketched here 712 ...
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