NMR - Example1 :Examples Example1 C4H8O MW72 :theansweris1....

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3/31/2017 Example 1 1/3 Spectroscopy Tutorial: Examples Example 1 C 4 H 8 O MW 72 First calculate the degree of unsaturation: the answer is 1. This means that the compound has four carbons and an oxygen, it can have a carbon­carbon double bond, a carbon­oxygen double bond ­ a carbonyl , or a ring. IR Spectrum A table of characteristic IR absorptions is available online: click on the link below. Note that this chart is also linked to in the frame to the left. IR Correlation Chart The IR spectrum for Example 1 is below. Since the degree of unsaturation indicates that the compound could have a carbonyl, let's look for that first, since carbonyl bands are strong and distinct. Carbonyls show up in the region 1760­1665, and specifically, saturated aliphatic ketone close to 1715. Sure enough, there is a band at 1718 indicating a saturated aliphatic ketone. Think of possible structures Now we know that the compound has a carbon­oxygen double bond, but there are still a few ways that this four­carbon molecule could be put together. Examples are below:
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  • Spring '17
  • DR.UMA DEVI
  • STRUCTURE, NMR, Interpretation, Spectroscopy, Infantry battalions of the United States Marine Corps, Carbonyls, ketone, methyl ethyl ketone, methyl, ETHYL, Butanone, carbon­oxygen double bond, link below. Note

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