PS3KEYF07 - Chemistry 391 PS3 KEY Fall 2007 1. a) wab =...

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1 Chemistry 391 Fall 2007 PS3 KEY 1. a) () , , ln ln b ab hot a bc V m cold hot d cd cold c da V m hot cold bc V wn R T V CT T V R T V CTT w =− = b) ln ln bd total hot cold ac VV R T n R T c) Use the adiabat relations for ideal gas: 11 1 1 c and Solve these for / and equate the results, . Therefore, or Therefore ln cold hot b hot a cold d cold hot cold b a b a c b hot c d c d d a b total hot cold a T V TV TT TVV V V V V V V R T n R T V γγ γ −− == = = ln ln db hot cold ca nR T T d) The heat withdrawn from the hot reservoir (isothermal process) where 0 ab U Δ= must be ln b ab ab hot a V q w nRT V = e) The efficiency is . cycle hot cold cold ab hot hot w T e qT T = <
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2 2. a) First calculate V c and V d . 1 1 1 13 5 2 1 3 1 1 1 1 5 1 3 ; 423 K 423 K 2.9649; 10.000 L*2.9649 29.649 L 873 K 873 K ; 423 K 423 K 873 K 873 K cc bb c c b dd aa d a TV VT V V V V V γ ⎛⎞ == ⎜⎟ ⎝⎠ = 3 2 2.9649; 3.500 L*2.9649 10.377 L d V = b) We next calculate w for each step in the cycle, and for the total cycle.
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PS3KEYF07 - Chemistry 391 PS3 KEY Fall 2007 1. a) wab =...

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