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CSE 331 Spring 2008
Homework 3 Solutions
1.
The following diagram shows how quicksort would operate on this list.
All lists are given after
the partitioning step.
Pivots are shown in
boldface
.
Only the sublist that quicksort actually
works on is shown for each call.
In this diagram, it assumed that quicksort works as given in the
text, only modified so as not to call insertion sort.
median3() swaps elements to find the pivot.
For the following diagram, median3() swaps the pivot to the far right of the list.
No other
swapping is done during the partitioning step.
This is different from the algorithm in the text.
quicksort(A, 0, 0)
233, 132, 327,
414
, 877, 542, 433, 986, 554
132,
233
, 327
132
327
433, 542,
554
, 986, 877
433
, 542
542
877,
986
877
quicksort(A, 0, 2)
quicksort(A, 2, 2)
quicksort(A, 4, 5)
quicksort(A, 4, 8)
quicksort(A, 7, 8)
quicksort(A, 5, 5)
quicksort(A, 7, 7)
233, 132, 327,
414
, 986, 542, 433, 554, 877
132,
233
, 327
132
327
433, 542, 554,
877
, 986
433,
542
, 554
554
986
quicksort(A, 0, 2)
quicksort(A, 2, 2)
quicksort(A, 4, 6)
quicksort(A, 4, 8)
quicksort(A, 8, 8)
quicksort(A, 4, 4)
433
quicksort(A, 6, 6)
quicksort(A, 0, 0)
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View Full Document2.
(a)
We are given a sorted list of N integers, with
O
(1) randomlyordered elements appended to
the back.
There are a couple different approaches we could take to sort this list in
O
(N) worst
case time.
Probably the most obvious approach would be to just run insertion sort. Since the first
N integers are already sorted, insertion sort would skip over them in
O
(N) time.
After that, it
would insert all of the randomlygenerated elements into their appropriate places in the list.
This
will take
O
(N) time per element, since the sort may have to search through most of the list to find
the correct place.
Fortunately, since there are only
O
(1) elements that are out of order, it will
take
O
(N) *
O
(1) =
O
(N) time to sort the whole list in the worst case.
Note that you could use a binary search to find the correct place for each element in
O
(log N)
time.
This would be faster than the
O
(N) sequential search used by insertion sort.
However,
even if you did this, you would still have to make
O
(N) swaps to insert each element into its
correct place in the array, so the complexity of the algorithm would not be any better.
(b)
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 Spring '08
 M.McCullen
 Algorithms, Data Structures, Sort

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