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Practice Test 3 - CEM 3Y5 fled“(15373 Nov 1067" ‘...

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Unformatted text preview: CEM 3Y5 fled“ (15373 Nov 1067 " ‘ V :i l. (30 points) Answer the following questions concerning the Deacon process (once used for making chlorine), using the thermochemical data given in the table below (all values relate to stande ambient temperature, 298 K, and 1 bar pressure) 2HC1(8) + '1/2 02(8) 2'2 H20(g) + C12(g) gas AH; (kJ/mole) _ 3 AG; (kl/mole) 8:98 (J/mole K) HCl —92 —95 187 3 H203 . —242 —229 189 C12 . o o 223 02 . o . o 205 a) Determine AHggs and A8393 for the production of one mole of C12(g) by the above reaction. b) Assuming AH° and AS" for the reaction to be independent of temperature, determine Kifit 900 K Student Name Student PID No. Section No. c) Ifone mole each of HCl, 02, C12, and H20 are placed in a 5.0 L container at 900 K, in which direction will the reaction proceed to reach equilibrium? (Assume all gases behave ideally.) ' d) Given the initial conditions of part (c), determine the mole fractions of all four components at equilibrium. (Assume that the change in moles of 02 in reaching equilibrium can be neglected in the Calculation.) Student Name Student PID No. Section No. e) Calculate AG fix the mixing process at equilibrium. 2. (25 points) 7 a) An ideal solution is prepared by mixing three moles of acetone with 2 moles of diethyl ether at 303K; The vapor pressure of pure acetone at 303K is 0.39 bar and the Vapor pressure of pure diethyl ether at this temperature is 0.78 bar. What is the vapor pressure of the solution? b) If the solution is sealed in a can that is initially evacuated and allowed to come to equilibrium. What are the mole fractions of acetone and diethyl ether in the vapor at 303K. Student Name Student PID No. Section No. 3. (20 Points) . Answer the following questions, given the data for NH3 listed below: AHvap = 23.4 'kJ/mole AHfus = 5.7 kJ/mole density of li uid = 1.33 cm3 density of so 'd = 0.89 cm normal fi'eezing temperature.= 195 K 7 a) The vapor pressure of pure liquid NH3 at 205 K is 100 mm Hg. Estimate the boiling temperature. of the liquid in a pressure cooker where the pressure above the liquid is maintained at 5 atm. (1 atm = 760 mm Hg, MNH3 = 17 g/mole) ' Student Name Student PID No. Section No. b) What is the temperature of an equilibrium mixture of NH3 solid and liquid at 100 atm external pressure? (Assume that the densities and AH data given above are independent of temperature.) 1 Student Name Student PID No. section No. 4. (25 Points) a) A vapor pressure curve for C02(g) dissolved in water at 274 K is shown below. Ifa bottle containing such a solution is sealed and plaeed under a C02 pressure of 10.0 bars, at what temperature will it freeze? (Assume that the solution is semi- ideal and that AHfus = 6.0 kJ/mole, MHzo = 18 g/mole.) b) What is the sign of AHsoln for this mixture at 274 K? CEM 383 Equation Sheet PV=nRT V= V/n Pm? 2P. P-=X,-sz 2:5: 0 i=gases 1" l - a ‘ RT RT a ’ I _ P= _ 1;, 22g: Z—1+VBP+CP2+DP3+ (V—b) V i ‘ ‘ _ 2 3 > Xi= n‘ ‘ ' Z=5Z=1+B[—l-)+C(ij +09) +... ”total. RT . V V V ' ’3RT Ews=3nRT/2, » V Cm: 7 ' — 8RT ' _ [ZRT c= — 7 . cmp— — n'M M _ 2" N ' 21(N) _ — . Z = — — Zl \[2—7rd {V} 11 2 V A=i IL: & Zl - r2 M1 ' w = - Pex,dV v ' . w '= -nRTln (Vz/VI) AU=q+w ' H=U+PV 8U 6H (8T j” p (8T )Rn AU=CV(Tz—T1) AH=Cp(T2-—T1) Cp—Cv=nR > AH=AU+A(PV) AU: qv = 'Cbomb(T2_ T1) ' PIX/17 = PZsz Ail—0 =2vAf H°(pr0d)—2vAfH°(reapt) A,H2 =»A,H1+A,CP(T2—Tl) A, H0 = ZBE(react)—2BE(pr0d) AS: ‘1'” - ' I As=nR1nE , T A VI T ’ T I AS=CPln—3- efficiency:1——i=l—w—I Tl I " T2 Q2 _ Tl _ q] , ' _ I C.O.P. — —— ASuniv —AS+ASW 20 T2 —T1 w . . A fil's H AmS=—R(nAlnXA+nBlnXB) Afilss= T ‘ f A H * T2 C AWPS= m” AS=j—d” T I Tb T, T _ _ _ T2 C A, S" = zvso (prod) — ZvS°(react) AS = J' 311w . Tl T T AS=CVln—2 - A,SZ»=A,SI+A,CP1n—Ti 1 1 AG = AH — TAS _ AA = AU — TAS dG = -SdT + VdP dA = -SdT — PdV Ara” = vaAfE" (prod) — ZvrAf50(reac) A_ _ _ AG=nRT1n Pi PZ—PI=—gln :2- In E =fli— T2 T’ 1 AV T1 7 Pl R T1T2 — — — 8V _ V=n1V1+n2V2 ' Vi:[—'J ,u‘i=Gi=[§—G—] . ani T p n], ani T,P,nj AmG = nRT(X11nXl + X2 1n X2) 101 = 2gp1 ' P P. ym H = .0 Tl . ‘ .= —'- : _ = _._L.. = l l “I “I +R nal at Pi YIXI at lbar a mo R. = KXi = K'mi ' ATf = Kfm-i ATb = Kbm-i ' MsalvRszlb - Kf,b=———= z=1—a+av v=v++v (1000g / kg)A,,H ' “m = (VJLZ + V_,Llf)+ RT In a: a: = 7/:th m: = (”1:9 m1“ )1” A,E= Afi" +RTan 13,6” =—RT1nK H a? — * p=products ln[ K2 ] _ ArH [T2 - Tl) Q— Hat, F1 — R Tsz ...
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