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# Problem Set 6 answers - W)me 59 W\5 n=o,35mol T=238.2<\4...

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Unformatted text preview: W)me 59% W) \5.\ n=o,35mol T=238.2<\4 vrmL vzswL .___._——- 03 \so‘rhefmcm. (ﬁvemibk M = 0 ) 13H :0 N=—MZTJ)H (Va/v.) 3 h (2.4L/> M’va MZL ‘QHENOg’B—l q = AWN I; 0 +115wa 3) =h5ﬂ03ﬂ my gm : Lay‘oafx =\543 3711 T 223555 E MP bH~Tms K/ =\~\«5x\0'3‘5\ b) \so’rmmxol, ‘srrevers‘xbh Pex Lomm ( DU, 83 and 66:: are s‘rcd‘e Funchons q= —N =K®.3*\OZ\$\ mL 2423K (3(3) + C02 ((5) *‘b 2C0 (<33 bra”: AMP“ "mfg" Arr—V 3 ISA)“ ~ TAVS“ 5(6) — A; A” = M“ M" = 5(Pv) ‘Mnk‘ﬂ = ETUAM =&%A‘ 0) ME” = A; Wicmmmndn ‘ A; H°[C(gmph'\’r€)] gJﬁLoﬂlmﬁ)‘ O k3/mo\ =\\,qo “mm (555 "’1‘ §0[C(diw\ond)] '3°[C(%mphﬁe)—] = 2,4 aImam ’557'5/moh K =\‘ 5:5 T/mot K! 0* 25°C '9 61 60 r 51W” Tﬁfst = mm W a 4 (WHO 3.3 YWBn/molvk) ~‘rhe conversion \3 mm sponhnmus 0d WK. Since NE} = Q and A3 “'9, (36 Counncﬁ be <0 ,(md-mus is never sponmneoug. E531 “bi Equah‘on me = (Ba/am = v Cib=VdP —i> @2411, = VCPz'P.) w—b Ch= e,-+v(i’2—P,i Molar quanh‘h‘es can be used 1 a2 2 " V AP (Used *0 ShiHEi for charge in P) For gmphiie (1nd diamond! G 2 (carciphi’re) = E, (graphi’rei + \7 (graphiie) AP 62(diamonci) = 5. (gdiamond) * Wdiamoind) AP Mow. “Wiese can be combined +0 Find Arc-)2 9 Arc)Z 451 (diaWiohd3 " ('51 (gmphi’re) = 6. (diamond) “TV (diamond) AP -— 6;, (amphiiC) ’ VQmphiiﬂ AP 3 D-(C'J‘ 4 [Wdimmiid ’ngpini’véﬂ AP Eur iiie prams io be sponianeouxs’ Aral <0 2,88 ﬂ/moi < 2.i><\0”1 m3 “Aim-moi up > 2,88 ﬂ/mol :Wlo‘bm ‘2.\ iii)"' m/bmimoi ~—————————--~«~ M3 = i1; .-\ bar 5 MAO" bar «—>\PZ > izixio’ibari M VGA] high pressme, ‘me. Conwisim oi gmphi’re in diamond becomes spon'iurieous. @ Tmeii (Rmimnid) “77-706 c0 YYiEIhiig (UL T='60°C meiiinca i3 endo'ihefmia -i> AH =6) meih‘rra reduces order—v AS ”- @ véocc >~77,7°c "4% mci’r'incd is spon’mrom ~+ A6 =6) EB b) Dvgm meJHrg on T =«T7J7UC, Again m4, [)5 :6) Since, T =Tme1+ , \$61 =0 Ca’r equlﬁbr‘xum) c3 mama oi T= 400°C Hgam BHJES :63 '\OO°‘C 4 -77°C ’4? no’r spon’mmeous ~> AC: =69 Gambia We, Tb For wafer ad" P‘xke‘s ﬁnk, h= 11’500 m p=poexp(7%fmh ave ~, zcum 31¢ qaoomimom‘ J m ) 52 mol gran 27%.2\< , ._= . 5836 P6 7 3M}. : ’Qmpﬂ (4., LL) mausxusrcmpexjmn Equahon Po R T Ta . )m (0,5836% 3 (J. _ 4., > A. Po ) . T amt #05535 : ~46106,2\<<_L_ 3 > 'Y 373% X _ 1 '06585 i 1 1KT=35\$K =85°C\ T «Aqoazz 373211 6.26 ’Tmemwsm bvapﬁ=3q.%U/mo\ * ’“(§?>”%‘Dﬂ(?“;'w‘=‘r> §n(ﬂz_):*%q.3*\031\" mom (4 ..._L_ > =~z.nz.z \m‘mn Wm 3,5343 50%..ZK 3515K 7 Y); ‘2 (\ahmkwmw ‘iOsH'M’rvM (’881q ’rorr) \6234 I auperwokd wa’rex EfeCZCbtx¥~1000 M3 :6) (We prams is sponhmous) L3H :63 We H667,ng \‘5 eXOH/lermfc m = 6) We ice \‘5 more. ordered Wm water 6.37 \l=7.E§L “m :LOCA HAW of H10 36.50% 2OOZTchﬂ ﬁnd T ad which 0 = Vapor pressure (\ook up) P=D\$2Tw,o 7010‘ (0‘ 06 I ’ T 760m 9 Y MW 781 \cmﬁ ‘ (412nm mchd NOT ;(o,22\ mmﬁg /°c)("T(°c)+273“c) =(,ZZlmmH8/°C)(T) +6o.3mm me We ‘OUQL N6, MOON Mcﬁ 51’: 45°C, Who 3 W38 andoux P? 70.2 mm}? Thus. ‘Yhe +emp emhxre (L’r Nh‘mh had? of We woier 35 ‘m Hue vapor phage \3 450C, Yewersm\€.,bo\"nerrnd n=0.45mo\ (He) E :O'SQW‘ Vx "22L P2 40mm a) m : AH :0 . . T‘ 2560 q= BU’N'T'N 4—75M07'ﬂ {35:93:21 ..'._7__I7“.\._LL\$ 4%! T 2648.2! MD: M .xmg a O~(2C\E<.2K)('Z,6‘3/k) 417me3 i b§The pvesswe is Mr kem comizm‘w, and Hub [)6 ccmm’r be used ’m de’vermMG 'spov\'¥c31(\ei’ﬂ4w C3 The mcxﬂmum NOW. is dame When 13a = P1 w =’Pz(\;~z«v,) =«PZnZT(‘/P2~ Va) *vimamo’t 3113 mm! mm _j__, , ,L > \.\x\og”5 wilt mm 500%» W ___..——— Rrgon ‘- '5” = (\$.LHZO-89n1) T/moVk d6) '3 ~SdT OJ Comfcm’r pressure C11 4r Sdé '1 :J 2SdT 8' " 353.2% N: = — I (\mmMeAmoxmm 266.21: - (as/m ZO,%('T3nT'—Y)) *\*é.24x\053) 7333, '1. 2°: 3.1 ...
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Problem Set 6 answers - W)me 59 W\5 n=o,35mol T=238.2<\4...

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