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9-31 - 9-31 Equations Set 25 Problem 9.31 At the beginning...

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9-31 Equations Set 25: Problem 9.31 At the beginning of the compression process in an air-standard Diesel cycle, P 1 =1 bar and T 1 =300 K. For maximum cycle temperatures fo 1200, 1500, 18000, and 2100 K, plot the heat adition per unit mass, the net work per unit mass, the mean effective pressure and the thermal efficiency, each versus compression ratio ranging from 5 to 20 T 1 = 300 (1) P 1 = 100 [kPa] (2) s 1 = s ( Air, T = T 1 , P = P 1 ) (3) u 1 = u ( Air, T = T 1 ) (4) v 1 = v ( Air, T = T 1 , P = P 1 ) (5) s 2 = s 1 (6) v 2 = v 1 r (7) T 2 = T ( Air, s = s 1 , v = v 2 ) (8) u 2 = u ( Air, T = T 2 ) (9) P 2 = P ( Air, s = s 1 , v = v 2 ) (10) h 2 = h ( Air, T = T 2 ) (11) P 3 = P 2 (12) T 3 = T max (13) s 3 = s ( Air, P = P 3 , T = T 3 ) (14) CutOffRatio = v 3 v 2 (15) v 3 = v ( Air, T = T 3 , P = P 3 ) (16) u 3 = u ( Air, T = T 3 ) (17) h 3 = h ( Air, T = T 3 ) (18) s 3 = s 4 (19) T 4 = T ( Air, s = s 4 , v = v 4 ) (20) v 4 = v 1 (21) u 4 = u ( Air, T = T 4 ) (22) w cycle = w 12 + w 23 + w 34 (23) w 12 = u 1 - u 2 (24) q 23 = h 3 - h 2 (25) q 23 - w 23 = u 3 - u 2 (26) w 34 = u 3 - u 4 (27) η = w cycle /q 23 (28) mep = w cycle v 1 - v 2 (29)
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1500 K Run T max r w cycle η CutOffRatio mep q 23 [K] [kJ / kg] [kPa] [kJ / kg] 1 1500 5 321.6 0.302 2.655 466.9 1065 2 1500 5.625 350.4 0.3376 2.54 495 1038 3 1500 6.25 372.7 0.3679 2.441 515.3 1013 4 1500 6.875 390 0.3941 2.356 530.1 989.6 5 1500 7.5 403.6 0.4172 2.281 540.8 967.5 6 1500 8.125 414.2 0.4376 2.215 548.5 946.5 7 1500 8.75 422.4 0.4558 2.156 553.8 926.6
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