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Unformatted text preview: 1 2 3 4 5 6 7 8 Total MATH 1315 Exam 1 Instructor: C. Gunning Name: 1. 15 points Perform the indicated exercise: (a) Determine the equation of the line that passes through the points ( 1 , 4) and (6 , 5). m = y 1 y 2 x 1 x 2 = 5 4 6 ( 1) = 1 7 y = mx + b y = 1 7 x + b Substitute the point ( 1 , 4) (could have used the other one) into the equation y = 1 7 x + b to solve for b . y = 1 7 x + b 4 = 1 7 ( 1) + b b = 4 + 1 7 = 28 7 + 1 7 = 29 7 y = 1 7 x + 29 7 (b) Determine the equation of the line that has a slope of 2 and passing through the point (1 , 3). y = mx + b 3 = ( 2)(1) + b b = 3 + 2 = 5 y = x + 5 (c) Determine the equation of the line that has xintercept (2 , 0) and yintercept (0 , 3). The yintercept being (0 , 3) automatically gives us that b = 3 in the equation of the line y = mx + b . We just need the slope, m , now. m = y 1 y 2 x 1 x 2 = 3 2 = 3 2 y = 3 2 x + 3 1 2. 15 points Your salary was $ 28,500 in 2004 and $ 32,900 in 2006. If your salary follows a linear growth pattern, what will be your salary in 2010? The phrase linear growth pattern is a dead giveaway that we can find a linear function f ( x ) = mx + b (where y = f ( x ) is salary in $ and...
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 Summer '08
 GUNNING
 Math, Algebra

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