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Unformatted text preview: 1 2 h = 4.0 m v = 8.0 m/s Physics 7B-A Quiz # 1 DL sec: Name: 1/16/08 last, frst Codes: grading use only 1 2 h = 4.0 m v = 8.0 m/s 1.)Apipewithuniformcrosssectionalareaisinitiallyhorizontalandrisesfromtoaheight4.0 maboveitsinitialheightasshown.Thefluidflowinginthepipeisincompressibleandany dissipationcanbeignored.Theinitialspeedoftheflowatpoint(1)is8.0m/s. =900kg/m 3 a)(50%)Whatcanyoudetermineaboutthespeedofthe flowatpoint(2)? dV dt = vA v 1 A 1 = v 2 A 2 . Wearegiven A 2 = A 1 v 1 = v 2 , Rubric Question 1: 5 pt (I) - Applied I=Av to find the velocity remains constant 2.5 pt (A) - Found that the velocity remains constant for either the wrong reason or no reason 0 pt (V) - Fundamental error in reasoning or no answer given...
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This note was uploaded on 07/31/2008 for the course PHY 7b taught by Professor Taylor during the Winter '08 term at UC Davis.
- Winter '08