1•
2•
h = 4.0 m
v = 8.0 m/s
Physics 7BA
Quiz # 1
DL sec:
Name:
1/16/08
last,
first
Codes:
grading use only
1•
1.)
A
pipe
with
uniform
cross
sectional
area
is
initially
horizontal
and
rises
from
to
a
height
4.0
m
above
its
initial
height
as
shown.
The
fluid
flowing
in
the
pipe
is
incompressible
and
any
dissipation
can
be
ignored.
The
initial
speed
of
the
flow
at
point
(1)
is
8.0
m/s.
®
=
900
kg/m
3
a)
(50%)What
can
you
determine
about
the
speed
of
the
flow
at
point
(2)?
dV
dt
=
vA
õ
v
1
A
1
=
v
2
A
2
.
We
are
given
A
2
=
A
1
õ
v
1
=
v
2
,
Rubric Question 1:
5 pt
(I)  Applied I=Av to find the velocity remains constant
2.5 pt (A)  Found that the velocity remains constant for either the wrong reason or no
reason
0 pt
(V)  Fundamental error in reasoning or no answer given
b)
(50%)
What
can
you
determine
about
the
pressures
at
points
(1)
and
(2)?
Using
our
energy
density
model,
1
2
ρ
v
1
2
+
ρ
gh
+
P
1
=
1
2
ρ
v
2
2
+
ρ
gh
+
P
2
.
The
change
in
kinetic
energy
density
is
zero
because
there
is
no
change
in
speed,
and
taking
our
zero
point
for
potential
energy
to
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 Winter '08
 Taylor
 Physics, Logic, Trigraph, minor math error, gh + P2

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