This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 2/5 Graders comments: P(AuB) = P(A)+P(B)  P(AnB) • Find the probability that a single toss of a fair die will result in a number more than 4 o the probability that a single toss of a fair die will result in a number greater than four is 2/6 because there are only two more numbers that are greater than four. Therefore, out of all six possibilities, their possibility of showing up would be 2/6. answer: 2/6 5/5 o each face has a probability of 1/6. 4  1/6 5  1/6 6  1/6 These probabilities add up to 3/6 or 1/2. 5/5 • Find the probability that a single toss of a fair die will result in the number 4 or less if it is given that the toss resulted in an even number. • Find the probability that a single toss of a fair die will result in the number 3 or less if it is given that the toss resulted in an even number....
View
Full
Document
This note was uploaded on 03/11/2008 for the course ECE 315 taught by Professor Clark during the Spring '08 term at Cal Poly Pomona.
 Spring '08
 Clark

Click to edit the document details