308-36-37 - NCSU MAE308 36 Water is circulated from a large...

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MAE308 36. Water is circulated from a large tank, through a filter, and back to the tank as shown. The power added to the water by the pump is 200 ft•lb/s=271.16 W. Determine the flowrate through the filter. 200 ft = 60.96 m 0.1 ft = 0.03048 m s s P mw Qw   Pump s P P w Q vA     (1) = free surface, (2) = another location on free surface 2 2 2 2 1 2 1 1 2 2 s L p p 1 1 fL v v v gz v gz w K 2 2 D 2 2 D UD (999)v(0.03048) Re 27187v 0.00112 (1) p 1 = p 2 , z 1 = z 2 , v 1 =v 2 2 v K 2 v D fL w 0 2 L 2 s 2 v K 2 v D fL vA ρ P 0 2 L 2 Then 2 2 2 271.16 f(60.96) v v 0 [0.8 5(1.5) 12 6 1] (0.03048) 2 2 (999)v (0.03048) 4   2 2 v 65 . 13 fv 1000 v 0 . 372 0 65 . 13 f 1000 0 . 372 v 3 (2) Assume f=0.04 ) 2 ( v = 1.907 m/s ) 1 ( Re D = 51842 Moody f = 0.039 ) 2 ( v = 1.9188 m/s ) 1 ( Re D = 52168 Close – best we can do with precision of graph
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This note was uploaded on 08/01/2008 for the course MAE 308 taught by Professor Danby during the Fall '08 term at N.C. State.

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308-36-37 - NCSU MAE308 36 Water is circulated from a large...

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