308-32-35 - NCSU MAE308 32. Oil of SG=0.87 and a kinematic...

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NCSU MAE308 32. Oil of SG=0.87 and a kinematic viscosity ν =2.2x10 -4 m 2 /s flows through the vertical pipe shown at a rate of 4x10 -4 m 3 /s. (a)Determine the manometer reading h . (b) What flowrate (magnitude and direction) will cause h =0? Why is there a non-zero pressure difference in this case? SG = 0.87, ρ = 869.13 kg/m 3 (a) Q= 4×10 -4 m 3 /s 273 . 1 D 4 π Q A Q v 2 = = = m/s BE for fluid flowing from (1) to (2) f s 2 2 2 2 1 2 1 1 w w gz v 2 1 p gz v 2 1 p + + + + ρ = + + ρ SG = 0.87 SG = 1 h 4 m 20 mm Q 75 . 115 10 2 . 2 ) 02 . 0 )( 273 . 1 ( ν vD Re 4 D = × = = - Laminar flow 6 . 89 2 ) 273 . 1 ( ) 02 . 0 )( 75 . 115 ( ) 4 )( 64 ( 2 v D Re L 64 2 v D fL w 2 2 D 2 f = = = = J/kg f 1 2 2 1 w ) z z ( g p p ρ + - ρ = - (1) 8 . 43779 ) 6 . 89 )( 13 . 869 ( ) 4 )( 807 . 9 )( 13 . 869 ( p p 2 1 = + - = - Pa 1 2 m 1 2 p ) h h ( g gh gh p = + ρ - ρ + ρ - gh ) h h h ( g p p m 2 1 2 1 ρ + + + ρ - = - , 4 ) z z ( ) h h ( 2 1 2 1 = - = + m g 4 h ) ( g gh ) 4 h ( g p p m m 2 1 ρ - ρ - ρ = ρ + + ρ - = - (2) ) 13 . 869 999 3 . 1 )( 807 . 9 ( ) 807 . 9 )( 13 . 869 ( 4 ) 8 . 43779 ( ) ( g g 4 ) p p ( h m 2 1 - × + = ρ - ρ ρ + - = h=18.5 m (b) Equation Eqs. (1) and (2) g 4 h ) ( g w
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308-32-35 - NCSU MAE308 32. Oil of SG=0.87 and a kinematic...

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