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Problem # 1For the simple pipe system shown in the figure, the pressure are p1=14 kPa, p2=12.5 kPa, and p3=10kPa. Determine the head loss between 1 and 2 and the head loss between 1 and 3. The discharge is 7 l/s.The energy equation between 1 and 2 is: 21L22221211hzg2Vpzg2Vp−+++=++γγg2Vg2V2221=Whereand z1=z221L21hpp−+=γγm153.0mkN79.9kPa5.12kPa14pph32121L=−=−=−γ
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