Problem # 1
For the simple pipe system shown in the figure, the pressure are p1=14 kPa, p2=12.5
kPa, and p3=10kPa. Determine the head loss between 1 and 2 and the head loss
between 1 and 3. The discharge is 7 l/s.
The energy equation between 1 and 2 is:
2
1
L
2
2
2
2
1
2
1
1
h
z
g
2
V
p
z
g
2
V
p
−
+
+
+
=
+
+
γ
γ
g
2
V
g
2
V
2
2
2
1
=
Where
and
z
1
=z
2
2
1
L
2
1
h
p
p
−
+
=
γ
γ
m
153
.
0
m
kN
79
.
9
kPa
5
.
12
kPa
14
p
p
h
3
2
1
2
1
L
=
−
=
−
=
−
γ

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