physics lab 9 - March 7 2015 Lab Report for EC1 VI-1 The...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
March 7, 2015 Lab Report for EC1 VI-1: The data from table V1 can be found below. The values of R exp and the percent difference are found calculated below. R 1 = 30 Ω σ I = 0.5 mA σ V = 0.001 V Resistor A Resistor B Resistor C Resistor D V 3.049V 4.471V 8.039V 10.217V I 20mA 20mA 20mA 20mA R exp = V/I 152.5Ω 223.6Ω 402Ω 511.0Ω R m 148.0Ω 216Ω 385.0Ω 983.0Ω Using Ohm’s Law and the voltage and current from our measurement, we were able to obtain the Resistance of each resistor. Using the equation from EC0, we were able to calculate uncertainty. Resistor A σ V = 0.001 V σ I = 0.5 mA = 0.0005 A V = 3.049V I = 20 mA = 0.020 A I V R R 3.049 V 0.020 A = 152.5 Ω 2 2 I V R I V R R 152.5 0.001 V 3.049 V 2 0.0005 A 0.020 A 2
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
R 156.5 0.0250021513  5 . 156 0500040827 . 0 R = 3.912836675Ω Yes, the DVM measured resistance does fall into the range determined from the measurements of voltage and current. Resistor B σ V = 0.001 V σ I = 0.5 mA = 0.0005 A V = 4.471V I = 20 mA = 0.020 A I V R R 4.471 V 0.020 A = 223.6 Ω 2 2 I V R I V R R 223.6 0.001 V 4.471 V 2 0.0005 A 0.020 A 2 R 223.6 6.250500254*10 ^ 4 R 6.250500254*10 ^ 4 223.6 = .1397611857 Ω
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern