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Unformatted text preview: 9.1 #8 a. Ho; μ =8.7 sec. b. H1; μ >8.7 sec. c.H1: μ < 8.7 sec. d. b. It would be right of the mean, because the test is for μ > 8.7 d. c. It would be left of the mean, because the test is for μ < 8.7 9.1 #10 a. a = 0.05 H0: µ = 85 H1: µ > 85 Since H1: µ > 85 mg/100 ml, this is a righttailed test b. Since the x distribution is normal and σ is known, use the standard normal distribution. z =(93.8 – 85) / (12.5 / 2.83) = 8.8 / 4.42 = 1.99 c. P(xb < 85) = 1  P(z > 1.99) = 1  0.9767 Pvalue = 0.0233 d. Pvalue <= alpha is false. We do not reject H0 The data is not statistically significant. e. pvalue less than the significance level we reject the null hypothesis and conclude the alternate hypothesis is true. 9.1 #14 a = 0.01 H : µ = 28 H 1 : µ ≠ 28 H 1 : µ ≠ 28, this is a twotailed test b. z = (32.7– 28) / (4.75/ 2.65) = 4.7 / 1.79 = 2.63 c P(z > 2.63) = 2( 0.0043) Pvalue = 0.0086 d....
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 Spring '08
 hill
 Null hypothesis, Statistical hypothesis testing, Ronald Fisher, alternate hypothesis

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