HW_4_solutions

HW_4_solutions - CHEM 150 HOMEWORK #4 Due: Monday, 11/6/06...

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Unformatted text preview: CHEM 150 HOMEWORK #4 Due: Monday, 11/6/06 . Calculate the standard potential for the reaction ZnCO3(s) + 2e" = Zn(s) + C032'(aq) foanC03 having Ksp=1.4X10'”. E9 a ., I My! . The following cell was found to have a potential of 0.512V: Pt(s) | H2 (1.00atm) | HA (0.200M) | | SCE Calculate Ka for HA. {1 Kat r: #57516“ . For the cell, Zn(s) lZnCO3(s) | C032'(aq)l | SCE ‘ Determine pC03 if the potential was 0.989V (you will need E° from #1). [9ng 7-1 . A 1.728g sample ofa Pb/Cd alloy was dissolved in acid and diluted to exactly 500mL. Titration of a 25.00mL aliquot at a pH = 10 in an NH4+ /NH3 buffer required 43.60mL of standard 0.01080M EDTA and involved both cations (Pb2+ and CdZU. The cadmium ion was then masked by using an HCN/NaCN buffer to bring the pH of a second 25.00mL aliquot to 10; 32.70mL of the 0.01080MEDTA standard was used in this titration and involved only the Pb2+. Calculate the respective percentages of lead and cadmium in the an” 1’1): tilt.th 5}; (:1: (.5152 33'; . Consider the following redox reaction: /"\‘ “g2 S(NH2)2 + 4Br03' + 3H20 = 3CO(NH2)2+ 3so42' + 4Br' + 6H“ 1 (a) Identify the atoms which are oxidized and reduced. gammy (b) Determine the number of electrons transferred. 5 63.x «715er (C) Write the balanced half-reactions. ‘ t ’2"? <f- f‘mw {'0’ 5t? ‘52 .53 i“- . . The following cell was employed to determine pSO4 of a solution: SCEI |HgZSO4(sat'd), SO42'(XM) | Hg . . {\ -. J" Calculate the pSO4 1f the potent1al was 0.506V. I; “ta/Ll- ~-- 0 If EEC/3012006” ’C ‘ 1'50 HWWK #5 Own AjnzhCa/s) v-~> 2m) + ((3743:) E“ —' ? ZnCOjé'zw “2 257?) + C"92‘(;z.) KSF : [K373326052] _- Mxtcf" Zn’h/éf} f 26' -»—.————~> 2m) E“.- ‘0762 V (anyway; E543: Ed',+ Ea» ; ‘5).762 +~032m§7 V F”:— - (,03306‘71/ ' Hal (\OOJQNHH/Ojomfl)” SCE ER)": 0332 1/ Ex : ~ (Ehkfi): -(amwomw z—omzv _ L E; -—0.27/‘v= ’0 V 0-054”) ( A 2 - i / L/ ” (1% Q) 0 \ kg :m 262% NW 1. i a?“ " (0n '1 .- Kg W]? M m :19er 2/4/11 / Z’A‘} [(73%wa {Wm :— 0-100 51/ [/13 3271‘? = Zozfflxrd‘m _ 2615mm ‘;< ; p 916259qx(0”5)1 , ’7 « CW _f.:.._--_.... : pméqéwcca .Dli 5 -"\ C1 31 : 3,. XIO —d____r_..-/' L: _ ___.._. __ _ ____ .;.—_. _____— q. . .___ _____ ___ _ _'____ ()(Pr‘oé-fi3l 23m) 2 Zai’éwéy (05%) H 5,6,5 "EEZCWWW (FC'OJI :‘P 36— in r 4‘ V ea.» _ _, _ / 2“ch ‘ :v A 0.09% M '7 E — E; 3 ~ 5% ) (a T lay/co) +O‘I37‘v: OMN 4 UV 4 £95937) [(0517 (~+ 1 (i4 V/Q 10% 7: (0.65?- - 0‘th —- H )(pfii‘éafi> : ~1Lmqq3 -— (a; 403nm;- ~. mo f___,/ rarm' .','.':JJ'I.1ri.-1 .' é? 2 00 Cz(f 1 dI/o- {9 ‘ I A. - H)" - / J ' M 7 -- Zioo-ML {MMZQ Qme jgoorfiLKFchw)mm i W - "r X agguwa ¥ HA1» (EIQT/J~7F/[E0Vr) #3: 60- ML 0. 01080 HEOTH 3170M aodmfl EOM (PM "' c c’) ' a (0-1!) 64M 0H; 10 v H: ID i q __ IUHJ/M-g ) HCJ/NaCNJ/ K6) are Va}: lave) V V V . ‘ I PME’DTH) 5i (Miser/U - PMEW} . x ,/ . , (Vb-w) , / ’ , ‘ ~— , _ ‘ - \ - ' / - , t / 0.0 zwwfi”t0w+ 60-;wL“-E-t9rf{‘ / Imam.) “9+ ( IiWL—‘P‘W 2““ 500% \ (_._ .. _, "MN —--- -- - \X J‘— I ' X!“’+"":Td—" ‘ I (buchyl San/k \_ “LE/9+4 {#Léwfk ( lWrfi’tfiTfF ¥3~°WE ’ f] \ \ ‘ / _ (PINK!) :’ Mun)! 2M?“ ? flu”! San/Hi '/~ I A r V r f _, ’0. O( Odo miskei-E’Ol‘flh 52. 7O‘xL4E93r/F— 1 1M 1 fl, 1 4%? q _ 50 0M; x A __ __' _._ _..-._—_ K , m“ x —:—-—~.——~\ - I (—— ————fi K I X 2 5.. C- 0 “4—” X { wa {‘q‘ I Saw/4L2) :— amt! Sam/C”? {mo-l cu : Mr MW)» Pb :@m7¢ - 7.06%“! 2~55W~M Cc" : V/MQEZjL 244.6% a): — T MWOI (“I . [Hy-q”: " (of , /)M6L{l§blm)’€ - , 5 lS‘iam’z 6“; ("@711— ‘9‘ '7:::Té?‘7L€-_ 1. 72m? 26/804 : #3321 7 532m] / M‘_— / . 330631on P15 saga-Pb _ a ‘(fi't‘fiUt—bfifQ" ’( 4W: fié " X (t, , l £006 How/V prob #5 fliCSOUIUOL Jr Wig" + 33w 5 BCOmH‘zL + 35027” wax-fair a) IJeJQ-gfiifgm wl/ICJ1 41re_ _cv;§2c1fzc:j2 , an») wlh‘th We re-(tice'j By"; “#uw— “> 6amqu {a '- bl: h r _ . .. H C) _____‘_7 0‘" oxygen i>_ M0+>P€2170Xttl . r . . . ____ Maui? ea {.3 VM (Lf'ejcx-wé) 2— V 6+ Hum“ ' ' ' "" "' '-r‘----—'———~\ 1* : _§__—:_-———————‘_ 7 5 Seal (my (5 o‘xw{ {gee-p "7' m “*4 . . ~/ i i“, V 1 ., ‘ _. C W) C” (arsz ('3 hof‘ reciom-J g .. 3. _ _ . ‘f - [U .y—__.w N ‘ 1n .‘ Hva F) H 8+ Fame»? #8493 + 12 “Lo 1—24; >45; 4. quH- 13°: +0.6l3V 350‘!" + 3Com“); + who + up ‘24:— TEJRZQ HA SKHH‘J-‘Tj‘ “wt +m ham rat/{mu w” 7699! He H 6+ 3‘64 0 (Ton _ Ell/OS/ZOoé ( CHE H-ISo mm sjmutgfl Damn I Prbc‘ “fillsoq (“MIL Sci-(2’11), EH“: J"6.500/ €50“ 3.? *"' 0.0 4 E "" Er *- E_ : — “5’6 {OJ(Q))_ E565 'G‘om Arfiulhc 2¢—+HhSoq(s) 721+}w + 50“"5?) E°:+O.6WV ...
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This note was uploaded on 08/06/2008 for the course CHEM 150 taught by Professor Buratto during the Summer '08 term at UCSB.

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HW_4_solutions - CHEM 150 HOMEWORK #4 Due: Monday, 11/6/06...

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