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Exam1 Key - (15 pts total/3 pts each) Multiple choice....

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Unformatted text preview: (15 pts total/3 pts each) Multiple choice. Circle only one answer. i) An aqueous solution at 4°C has a concentration of l ug/mL which is equal to: 0 [(a) 1 ppm\ (b) 1 ppb (c) 1% (d) 0.001 /0 ii) Which solution is more a 'dic? (21) NaCl [(b) (NH4)2SO4 (c) NH3 (d) NaCN iii) Given 0.0010 M solution of HNO3, the pH is (with appropriate significant figures)? (a) g (b) go 2.00 (d) @000 iv) The equivalence point of an EDTA titration of metal MM occurs when: (20 [MM] = [Y4'] (b) om“: 0m. l (c) mol M1”: mo] EDTA! (d) [MM] = [EDTA] v) How many significant ' ures in [Co3+] = 0.0060 M? (a) 3 (b) 2 (C) 4 (d) l (15 pts total/3 pts each) True or False. i) The solubility of SrSO4 is higher in 0.01 M NaZSO4 than in pure water. Fast ii) The conditional formation constant Kr, for a general EDTA complex ZnYZ' is smaller in 0.1M NH3 than in 1.0M NH3. Fm) Ere, iii) Consider the following reaction at equilibrium in aqueous solution, C6H5NH2 + H20 2 C6H5NH3+ + Addition of 10 mL of water shifts this equilibrium to the right. @364 iv) If the total phosphorous in a fertilizer sample is 25% then the total phosphorous given as percent P205 is less than 25%. EU *9; vi) A solution of NH4NO3 has a pH greater than 7.00. False, 3. (20 pts.) An alleged drunk driver has his blood analyzed for alcohol content. The legal limit is 0.100%. Based on the following 4 repetitive measurements, the driver is charged with DUI. Is this the right decision based on 90% confidence? Is this the right decision based on 98% confidence? Blood alcohol content (in %): 0.103, 0.108, 0.116, 0.113 '32 = ((5.103 + 0.10” o.ut+o.n33 520 x (mm?) '7‘ ; 0. 00512.72 + 0,001.13 2. \Drivfr l|5 .__————+——-—-——l 0.13 Me 0.1:} «bat 4h legit—l m 4« #07: mm“ 13m: 6'“ (.1 s41\(o.oo t—‘r’2\ C11]? = um i “##2## Cree : 0.1121 0 “3° 7' 'TlmEre. is ac Jame (Jul 93% mph—AL; hawk—4 in it W 0.0%} cm (5.113 MM” 4:“ [£304 1M. ‘ M, xbunt: {Aka f I HA 5. (20 pts.) Calculate the pH of a 250.0 mL solution containing 0.578g of salicylic acid (138.00 g/mol; K3 2 1.05 x 103) and 1.460g of sodium sallcylate (159.99 g/mol). A, 0 mitt z W : LHSWQ- M = 0 230011 I 4W3 i 1 MIL“ ,t 4414.95 w : 3.mmo'zM = [H 0.231% a: ma "PH = ¥Km+ :3 23451 4' l0} LLlsil'o‘l : 2.34“! + 103 (“19m = 2.0m 4— 0.332 1P4: 3.311L 4. (20 pts.) The calcium level in small blood—serum samples can be determined by EDTA titration using a microburet. If a 100.0 uL serum sample is titrated with 0.00122 M EDTA and 0237 mL is required to reach the equivalence point, calculate the mg Ca (40.08 g/mol) per 1000 mL. 2+ ‘ '- o g \ 0.00l22. mml'EN‘A mm?le =mmlEprt~ (Ollmq AMM‘ Y ID. 4 mm! _. - 2.8‘me'4wlcafri 4mm: : 1'MXm.zmflm~t+ \ MINI ‘7— z} 4 U‘ " 1+ lilsqwo % * 1.IS"IX|Q rush M . ’ Co 1000 M Wm 6. (20 pts.) A 100.0-mL solution contains 0.20 M formic acid (Ka = 1.77 x 10‘4). Calculate thei‘change‘} in pH when 200.0mL of 0.10 M NaOH is added to the solution. A“ mics/u; 41m“ i as; it. “Ewimdfilwbn ROUGH +0H’ ——3 H20 'l' PFC”- ‘(J 2Q. ml 20. Ml (é 95 2.1}, ml 20. MM‘ fr cgs =45 Zita-«l D 30004. g; 94’ ¢ e1 (emf-x) 7‘ X -H 7' 1 K I Kw _ l-OLW .— Sitsww” = X '2 X '1 b " K“ “ i-ttxh‘” @wmfig gmm \L .H , - -3 Din; "mm 3 m 5mm M ...
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This note was uploaded on 08/06/2008 for the course CHEM 150 taught by Professor Buratto during the Summer '08 term at UCSB.

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Exam1 Key - (15 pts total/3 pts each) Multiple choice....

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