Exam2.InformationPage.2008

Exam2.InformationPage.2008 - CONSTANTS: R = 8.3145 J mol1K1...

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CONSTANTS: CONVERSION FACTORS: R = 8.3145 J mol –1 K –1 1 atm = 760 torr R = 0.08206 L atm mol –1 K –1 1 A = 1 C/sec N A = 6.022 x10 23 atoms/mol 1 V = 1 J/C F = 96,485 C / mol 1 L atm = 101.3 J EQUATIONS: E = E o F n T R ln Q zero order: [A] = – k t + [A] o k 2 [A] t o 1/2 = E = E o n 0.0257 ln Q at 25 o C first order: ln [A] = – k t + ln [A] o k 0.693 t 1/2 = E = E o n 0.0592 log Q at 25 o C second order: o [A] 1 k t [A] 1 + = o 1/2 [A] k 1 t = K ln F n T R E o = t F n I = Δ G = Δ H T Δ S Δ G = – nFE k = A e –E a / RT Δ G o = Δ H o T Δ S o Δ G o = – nFE o A ln T 1 R E k ln a + = Δ G o = – RT ln K Δ G = Δ G o + RT ln Q = 2 1 a 1 2 T 1 T 1 R E k k ln PERIODIC TABLE 1A 8A 1A 2A 1 H 1.008 3A 4A 5A 6A 7A 2 He 4.003 2 3 Li 6.941 4 Be 9.012 5 B 10.81 6
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