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Unformatted text preview: PHYS 218 - SOLUTION TO ASSIGNMENT 4 23 Feb 2007 By Chung Koo Kim e-mail : email@example.com 1. String with a massive bead Lets suppose that the sinusoidal wave is incoming from the left. The wave equations of left and right side of the mass can be written left = e ikx + Re- ikx right = Te ikx so that the left has both incoming/reflected components and right has only outgoing transmitted component. Remarks. The following forms may be more general and familiar: left = A 1 e i ( kx- t ) + B 1 e- i ( kx + t ) right = A 2 e i ( kx- t ) Pay attention to the signs of kx and t . Waves propagating toward the positive x direction should have opposite sign for kx and t , and same sign for negative x direction. And we may replace the i in the above equation by- i without loss of generality at least for our purpose. But for later consistencys sake, particularly in quantum mechanics, we keep + ikx for wave toward (+x) and- ikx for (-x). You will learn that e ikx has positive momentum when we apply momentum operator p = h i x . And since we are mostly interested in the relative ratio of the coefficients only, we divide the equation by A 1 and replace B 1 /A 1 = R and A 2 /A 1 = T . Of course we took the common factor of e it out. Then we get the first set of equations. To match the two solutions at x=0, we should find two boundary conditions: left ( x = 0) = right ( x = 0)- left x x =0 + right x x =0 = m 2 right t 2 The first one comes from the continuity of the string, and the second one from Newtons second law applied to the vertical component of force. The ( x, t ) in the second equation can be either left ( x, t ) or right ( x, t ) since the two are the same at x=0. Note that we are in practice thinking of the limit approaching zero from the left and right, when plugging x=0....
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This note was uploaded on 03/13/2008 for the course PHYS 2218 taught by Professor Wittich,p during the Spring '08 term at Cornell University (Engineering School).
- Spring '08