KeyM147finalf05

# KeyM147finalf05 - for diﬀerence = 2 4 z = 1 75 p-value =...

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MATH 147 FINAL EXAM Fall 2005 December 14, 2005 Answer Key Part I True/False 1. T 2. F 3. F 4. T 5 T 6. F 7. F 8. T 9. T 10 T Part II Fill in the blank 11. .92 12. -3 ; 4.33 13. iii 14. 0.5 15. 50 ; 2 Part III Multiple Choice 16. A 17. C 18. D 19. D 20. D 21. B 22. E 23. A 24. A 25. C 26. B 27. D 28. D Part IV Problems 29. Null Hypothesis: His car averages 30 mpg. Alternative Hypothesis: His car averages better than 30 mpg. Use t-test; Degrees of freedom = 15; t = -1.69; p-value is between 5% and 10%; The result is not signiﬁcant; Do Not Reject the Null Hypothesis. In non statistical language, the data do not support the claim that the car averages better than 30 mpg. 30. (a) y - 1500 200 = ( 0 . 55 ) x - 100 25 · ; 30.(b) 1618.8 ; 30.(c) New Avg = 1618.8; New SD = 167; SU = -1.31; Chance = 9.68% ; 30. (d) Use the formula: ( 0 . 55 ) y - 1500 200 = x - 100 25 · and set y = 1530 to obtain x = 102. 31 SE ( for control ) = 12 / 50 ; SE ( for treatment ) = 12 / 50 ; SE
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Unformatted text preview: ( for diﬀerence ) = 2 . 4 z = 1 . 75 p-value = 8 %; Therefore Do not reject Null hypothesis. The data do not support the hypothesis that there is a diﬀerence in the teaching methods. 32. Null Hypothesis: The Die is fair. Alternate Hypothesis: The Die is not fair. χ 2 = 7 . 6; df = 5; 10 % < p-value < 30 % ; Conclusion: Do Not Reject Null Hypothesis i.e., The data do not support the hypothesis that Die is not fair. ; 33. (a) 3/10 ; (b) 2/5 ; (c) 3/20 ; (d) 3/10 ; (e) No. ; 34. Sample Average = 23% ; SE = 2.1% ; 90% C.I. : (23% +/- (1.65)(2.1%) or (23% +/- 3.47%) 35 (a.) The four possible progeny are: r/w, r/w, w/w, w/w; so that chance of red = 50% (b) EV = 1250; SE = 25; SU = 1.4; chance = 8.075% Updated 5/7/2007 1...
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## This note was uploaded on 08/08/2008 for the course MATH 147 taught by Professor Klimko during the Fall '07 term at Binghamton.

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