Quiz 4 - V 6‘ 9 and 25499.5.57"/Z'ZO04¢ Qaiz 4’ z...

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Unformatted text preview: \ V. 6‘- 9 @ and 25499.5 .57"'/Z-'ZO04¢ Qaiz 4’ z WWI I n = 46 a.) the 90% conf. int. for Y= 310 b.) the 98% conf. int. for f \{ (8/1399 0.) at th‘ level of confidence, What sample V size is required for ME = 5 2. “(e-:2“) II , J sample data 81, 65‘ ' , 95, 90, 83, 85, 79, 74, 64, 8'1, 58 n '4 L V 2 55/0/90 X‘77’é7 a.) the 95% conf. int for// (70.7 , 8 .59) ME = é. 9 / A{ b.) the 99% conf. int few/($7. r $7.4“? ME = 9 77 / c.) at th" level of confidence, what sam e si is required for ME = 5.5? 5 1,, 3,576)CID.90 8.: n = @473 ' 9" 5.5 III 2%“ Proportion data: x =1? n l— pm? Q95 a.) the 90% conf. int. forp (.390, 4 ME = 0 . a V b.) the 96% conf. int for p ( 33%Q‘2, ME = tag/5 Q 9‘ 9/ c.) at [email protected] of confidence, what sample size is required for NE = .02 I? = 255 3 . . . . . = _ n: 6 3 . d.) where We data 18 avallable, what sample Size 18 required for ME %I a 0K , e.) what is the standard deviation for this sample data? 0.54669 I ,, .4 . \ '\., 7 f.) what is the sample proportion (p-hat)? 0. I 9 C c) n @933 1(%L(.+m)(.sgp = .2568 : m ‘ fl 2 mi” as». 2667 n 9 fig.) ,r-vf. as :C 302% ...
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