Unformatted text preview: \ V. 6‘ 9 @ and 25499.5
.57"'/Z'ZO04¢ Qaiz 4’ z WWI
I n = 46 a.) the 90% conf. int. for
Y= 310 b.) the 98% conf. int. for f
\{ (8/1399 0.) at th‘ level of conﬁdence, What sample
V size is required for ME = 5 2. “(e:2“) II , J sample data 81, 65‘ ' , 95, 90, 83, 85, 79, 74, 64, 8'1, 58 n '4 L
V 2 55/0/90 X‘77’é7
a.) the 95% conf. int for// (70.7 , 8 .59) ME = é. 9 /
A{ b.) the 99% conf. int few/($7. r $7.4“? ME = 9 77 /
c.) at th" level of conﬁdence, what sam e si is required for ME = 5.5? 5 1,, 3,576)CID.90 8.:
n = @473 ' 9" 5.5 III 2%“ Proportion data: x =1? n l— pm? Q95
a.) the 90% conf. int. forp (.390, 4 ME = 0 . a V
b.) the 96% conf. int for p ( 33%Q‘2, ME = tag/5 Q 9‘ 9/ c.) at [email protected] of conﬁdence, what sample size is required for NE = .02 I? = 255 3
. . . . . = _ n: 6 3
. d.) where We data 18 avallable, what sample Size 18 required for ME %I a 0K ,
e.) what is the standard deviation for this sample data? 0.54669 I ,, .4
. \ '\., 7 f.) what is the sample proportion (phat)? 0. I 9 C c) n @933 1(%L(.+m)(.sgp = .2568
: m ‘ ﬂ 2 mi” as». 2667
n 9 ﬁg.) ,rvf. as :C 302% ...
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 Spring '04
 Young

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