{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Quiz3 - Your Answer Q kQ/r kQ r 2 CORRECT cannot be...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Quiz # 3 Physics 230 Prof. Hadley 1. Question: NOTE : For the following questions, use k instead of epsilon sub zero. This gives Gauss' Law as: E*A*cos(theta) = 4*pi*k*( Q encl ) THE PROBLEM: Refer to Figure 1 below. You have a conducting spherical shell of radius R with total charge -Q on it. At the center is placed a point charge of +Q. If r is the variable used in E(r) for the radial coordinate, using Gauss' Law, answer the following questions : FIGURE 1 Question 1. What is the magnitude of the electric field for r < R?
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Your Answer: Q kQ/r kQ/ r 2 CORRECT cannot be determined from the information given none of the above Points Received: 1 of 1 Comments: 2. Question: What is the magnitude of the electric field for r > R? Your Answer: Points Received: 1 of 1 Comments: 3. Question: What is the direction of the electric field for r < R? Your Answer: Points Received: 1 of 1 Comments: 4. Question: There is a discontinuity in the normal component of the electric field at r = R. Your Answer:...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern