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Unformatted text preview: dierent kinds (that is, there are no pairs among the ve cards)? There are 13 dierent kinds of cards, 2 through Ace. Out of those 13, we must choose 5. or each of these 5 cards, there are 4 suits, and we must choose one. Thus, the probability is ( 13 5 )( 4 1 ) 5 ( 52 5 ) I messed up and rewrote the same bonus question. The answer is again Alando Tucker. 1...
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This note was uploaded on 08/11/2008 for the course MATH 240 taught by Professor Miller during the Fall '08 term at Wisconsin.
- Fall '08