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distillation lab

distillation lab - CHEM212 Organic Chemistry 1 DISTILLATION...

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CHEM212: Organic Chemistry 1 DISTILLATION – V.P.C. Experiment #3 Introduction: The aim of this experiment was to determine the molar composition of a mixture of methanol and butanol, using simple distillation, fractional distillation, and vapor phase chromatography. Results and Calculations: Graph 1: Distillation curve for the simple distillation of methanol-butanol According to the distillation curve above, a 20.0ml sample of methanol-butanol should contain approximately 6.5ml of methanol and 13.5ml of butanol. Calculations: # of moles of methanol = (6.5ml x 0.79g/ml)/32 = 0.160 Mole fraction of methanol (N m ) = n m / (n m +n b ) = 0.160/0.308 = 0.519 # of moles of butanol = (13.5ml x 0.81g/ml)/74 = 0.148 Mole fraction of butanol (N b ) = n b / (n m +n b ) = 0.148/0.308 = 0.481 Therefore the volume composition of the mixture from the above graph is 52% methanol and 48% butanol.
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Graph 2: Distillation curve for fractional distillation of methanol-butanol According to the distillation curve above, a 20.0ml sample of methanol-butanol should contain approximately 9.0 ml of methanol and 11.0ml of butanol.
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