chap06 - PROBLEM 6.1 KNOWN A current loop having N = 20 A =...

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PROBLEM 6.1 KNOWN: A current loop having N = 20 A = 1 in 2 = 0.000645 m 2 I = 0.02 A B = 0.4 Wb/m 2 FIND: Torque on the current loop, T µ . ASSUMPTIONS: The magnetic field is oriented at an angle of 90 o to the current flow direction. SOLUTION: From (6.3) T NIAB µ α = sin The maximum torque occurs when sin α = 1, which yields ( ) ( )( ) max 2 2 20 0.02 A 0.000645 m 0.4 Wb/m T NIAB µ = = max 4 1.03 10 N-m T µ = ×
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