Phys2-T2 - PI-iY 2426: Engineering Physics 2 Exam 2-H: l3...

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Unformatted text preview: PI-iY 2426: Engineering Physics 2 Exam 2-H: l3 March, Ell-DE Name: LIE DU SSH: :2 i} (ll) (Last 4 Digits} ._. I-) A small metal sphere of radius, r, = 20 mm, initially,r has a net electric charge, Q = 165 ME. A second larger metal sphere of radius, r: = Eflfl mm, initially:r has a no net electric charge [i.e. net charge of zero). The centers of the two spheres are separated by a distance of d = lflfll) nun. rl=2fl mm : exit} I“ % r3=200 rnrn : D n W. What are magnitude (11C) and s_igg (+f—} of the net electric charges on each sphere (q, and :11) respectively after [hey are then connected by a thin conducting wire“? lCaution, use Si units. r- J" «a : t s Wth ,2 l l_ (ill I {i1 ’jl Cir.- / l a: -— —-I— ‘_-—I F: —' : L 5 -—-_ IRE]. {TL-ff. {it EF’ :11 F1 In .- i __ T I q: i __ .+ l J : rfi r/ h“; l1; L is; J / \R. _ s'} r111 _ Q _ t F1 ' L— :I/ “3" fit'- (—3. 2 ) 2 lg?) _."" _‘ "' n4, .' —— —-—~—._ ' L: {1‘ II I” " F; 1 ' j ' t- I ’ K h l2" XI ill" Hat .1! e' J 'l' J1 J l? ——— __ {j / ______ __ l j _, C I ,1 _ LO l if I F _ L P A J l p IJ I n X 2/}, "l "E." 2.) Answer the feliewing questions regarding the circuit below, r _ i i ,_ i “1:. I ii‘ ii? if} .J'l‘ : Ear-ext T " i2r: —" Rik-r - rd £13 I _ g - m : 2a) What is the equivalent resistance, R,” , ef the circuit? x7 i941 ; 1'2 jL/ W lb) What is the tetal eurrent, IT , through internal resistance, r '? Hint, use Ohtn’s Law, I-.- = 8.me . t , L / I : Flam ‘— 1: is] What is the terminal veltage, VT '5’ _ "I, _— t1“. —:r.t': 53’ : 5V 1d) What are the branch currents, II and I: ? Hint, note what the veltage is aeress eaeh resistor, then applyr Olim‘s Law. j I __ : : -1l-' : W _ : — _,]_ / .I I --- - 5,:- ' .I' la) What is the pawar dissipated in all three resisters, P, , Pl , and P3 '? , _. r_ .3. i __ ! Fr 3-” {Ti : 19-” "ii : r'-T' ,‘Th‘i/ | ..-.— 1-i- tfi' "r 1: Fl : 1: 1—3 ": —_' r, —_ : :3 / 1%? 3a.) What is the equivalent resistance, Rah , ef the fellowmg network if all resistere have the same value: R = 2!) KS7. ‘? r" 1 .3 T7, L'fLy/ 31:.) What is the equivalent capacitance, Cal, , of the following network if all eepaeimrs have the same ‘value, (3 = 2 HF ‘2' F Q; Len: : -— “Ft-Ire. W / M 4a) What is the capacitance, C = ?,of the following parallel plate capacitor, where the plate separation is, d = 5 mm, and radius of plates is, R = 5E} mm, and glass is between the plates {tt = 4.5)? Note, r-‘trea of plates = rtR2 . Caution, use 31 units. _ TTTL _— : Kt: #— : &.'2-am"HF "" 3 4.13] Assume that there is no net charge (q=[l) initially on the parallel plate capacitor. At time t={}, the switch (SW1) is closed and the parallel plate capacitor begins to charge. When completely charged, what is the maximum charge qr,“ on the capacitor? .. W a fllhhjwlf; C if _" [IEQyLGFH— : {:"?,5 3‘3"]— (3 : 3.15xlo'”¢ 4c] What then is the value of the electric field, E in Wm, in the gap?J y / _ i F . :- iii-"m 1 5i 3 fl “3 m 4.d) 1|What is the work , in Joules [l], done by the battery to charge the capacitor to a maximum charge qmm? Hint, this is the same as energy stored in capacitor. l} T -.rfll'tr'___ Gaff-3 .r of i : [y3_ Et’ at I503— --' W or _.. "1‘3 l a PD J 4.e] Which plate is positively charge¢@g'r Circle choice here. ... 1/ 4 5a} A parallel plate capacitcr cf plate area (A) and plate separaticn (d) is filled With two dielectrics, K1 and K2 , of equal area (NE). Shcw the capacitance is given by C { K] r // -.-[ : I I _.— n ct (Hint. Think of this as two capacitch in parallel.) _._-r*___"| I :11 MF/‘fll ,_ C +1 / 35: x J] a" 'l' ‘—t—' r' a u arts ’55: Mei:- ;'}__| —-—~ll-— _ fl Cl .‘H "n. ’a ,-: ‘2 “Manual *1 'k: 1— l: I'l- -—-—' “mg l I _ _'_ Ilk “'1 _ T— l a " .-" k-| all 9 5b) What must he the diameter cf an iron wire if it is to have the same resistance, R, as a ccpper wire 2.4 mm in diameter. hcth wires being the same length L“? Use 31 units! Hint, set RFE = RC“ , then preceed. E Area = m2 ={ed1y4 '20 pa" = 1.69 x HIE $1111 a” pa: = 9.36 x 10“: flmJ Elm, = 2.4“ mm Ella; 3 l-(Jr‘ fl -_ K‘Ea ‘1 IL— I ll -' I'D r” F— : PE? :— 33. Pm; 'T l_ in??? I] 1 A Ili—l-i—Ilpi-Clr‘ijlh—F I. Jig-E?) l"I r: _' PF Pr" A l l‘ — a a _ i — I" s. l t - -: : " “l 1’"?T 0* ' J A“ l j" PM a; film 'gilrw FISH '- J. ‘F _ ’ .31, _ q “I / :I [— fljrle)* “Lie 3'1 £175 )4" clef: \ I an r— 5 ll —| a Cr: {:6 K ...
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This note was uploaded on 08/26/2008 for the course PHY 2425,2426 taught by Professor Ronald during the Spring '08 term at University of Texas at Austin.

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Phys2-T2 - PI-iY 2426: Engineering Physics 2 Exam 2-H: l3...

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