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# Phys2-T3 - PHY 2426 Engineering Physics 2 Exam 3—9 15...

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Unformatted text preview: PHY 2426: Engineering Physics 2 @ Exam 3—9.: 15 April, ZEIUZ Name: Lac 0“ SEN: g '2 ”L 9 {Last 4 Digits) am 13 3:0 La) Fer the RC circuit abcve, calculate the time ccnstant, 'L'. T: RC. = agile gig“: =[:33l=0.0135 “a. M (w‘ab Lb) What is the maximum charge, gm.“ , in MS ? c = qm‘” E} qmmc cc 2 .5“ s AF: ‘scﬁczl if Le) What is the charge, q(t=36 ms), en the capacitor in w: assuming that it was initial] c]: e ﬁ'ee at [=0 '2' -*r’r y mg (in): C‘U’t('— .e D +3E/I‘I _ assﬂs mumps D = Mus-f): sum—mm) =-/ Ld} State which plate is positively (+) charged 1' 2 ? / 2. A metal wire trolley,r of mass, m, slides without friction on two horizontal conducting rails spaced a distance d apart. The track lies in a vertical magnetic ﬁeld B pointing up. A constant counter-clockwise current, I, ﬂows from the'positive terminal of the battery around the circuit. fﬂe: la} Calculate the Lorentz Force, F3, on the metal wire tr;lley. E=LE=¢€ a) ¥e = ”L15 2.13} Circle the direction of F3 here. To the left or to} Calculate the velocity, ﬁt), of the metal wire trolleyr of mass, m, if it starts at rost at i=0. Hint, use Newton’s Second Law, EF = nut, and v = at . \‘V a 5'1: t m g; 3.} A surveyor is using a magnetic compass twenty feet below a power line in which there is a stead},r current of lillfll| A. _ tat-aunt“ =etr~n 1=1ﬂ0A 5.2.31: In! * Im- r 1 ' "i A ----- I jut :: ”Tr flu-T Twig la) What is the magnitude of the magnetic ﬁeld, B in T, at the site of the compass due to the power line? Use 51 Units! B _ ﬂat :JCJa-i:(u“ wa'TTr-WDC‘wﬁj/ 1—5111: 3th EMT (Elna) 3b] What is the ratio of the magnitude of this field B to the earth’s magnetic ﬁeld, with horizontal magnitude of BM}. = 20 ”T ‘? 4.) A iong straight wire carries a current of i1 = 3D A, and a rigid rectangular wire loop carries a current of i2 = 20 A in the directions shown. Both wires lie in the vertical plane, but only: the loop'is free to move up or down. Ignore gravity. i1= 30A 3: 1 cm b=8crn _1 L=30cn1 Au“: [HT fin Tm/A i|=3ﬂﬁt 1122015.. ﬂ 4.13} Calculate the resultant all?“ the vertical direction, F in N, acting only on the loop, which is free to move, assuming the dimensions shown above? Use SI units! Eﬁtﬂt) = 113—13: '5 (3+!) Marcia .Iuo'tréaL aar.at(1 : M,[.L1L(a+bpa)_/ﬂui,ill_ b > .217 a [a nth) H d (Mb) I—... @t hr) (so)eo)(vm>( 3cm 1 411) Is the resuitant force, F in N, acting on the loop directed dotvn or gp? Clearly circle your answer here. / down or 0 5.3.) Calculate the magnetic ﬁeld B for a tureid of N turns and surfing a current I at the middle of the aperture. Assume that the windings have a rectangular cross seetinn of inner radius r, and an enter radius of n, and height of Ir. Hint, use Bram-id = itﬁINi’Eitr where N = # turns. ri=4ucm= A): ”“5" 2" rh=5iletu3 f N=lﬂ0ﬂturns M I=25A 5.13} What is the direction of the current, by right grin hand rule, in the windings in urder tn give the ﬁeld indicated? Indicate ynur answer by eireiing uni}: E nf the eheiees at the above ﬁggg. ...
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