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Unformatted text preview: PI—IY 2425: Engineering Physics l we
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Exam iiiA: 19 November. 2001 =  LOG DU SSH; 53 “LE {Last 4 Digits} Name: I.) A steel ball pt'ejeetile of mass, 111 = SCH] gun, is fired lterizentally from a my
gun with a spring eenstant. it = Silt} thn. The spring is initiallyr enmpt'essetl
frent its natural length by an amount, a = 5.1313 cm. Assume that there is an
frietten present, and mat the hall leaves the spring in its relaxed pesitien at
the end of the barrel, and that mechanical energy is conserved. Use 3] units! Min“ WW3 / I a
' "I" rf.
Ell—{J O 2/. {lit.1 a I'T'r‘—
'I: 5000'“ : ﬁe”
x~=5ﬂﬂ ent girﬁrt
.a) What is the muzzle veleeity, v“ in nits, cf the prejectite just as it leaves the
my gun? ﬂSSUI't'tB ne receil at the tey gun. Use censervatien nt’ mechanical
energy. with elastic potential energy U: i I: HERE? Use SI units! _ ‘r U '  .‘
Haiti);  (l: )5— ” a E {a}
I .1 .3 f ' rt't
if} t 1 19,11 : rmu' t 2’! F.
E 1
— jartlfrn _
t! * (it as 7“!) =
" e. flu—tibia Lb) What is the kinetic energy of the prejeetile just as it leaves the toy gun? Uy/ SI units!
1 .";'_"]'1:“'K.3;i CE (“9(5le : {j J— I“:
III
.rt
5’
ll L
.1 2.) The projectile from the previous problem, at = 51110 gm, is captured by a
ballistic pendultnn, M 2 25B gm. Assume that there is no Friction present it:
the pivot or due to air drag. rri—_.tlStilifg
M : cast: its; is} What is the velocity, ‘v’ in mats, of the system {m+l'v1), projectile plus ballistic
pendulum, just after collision, t={ll. it" the initial velocity of the projectile
just beﬁore collision, F0 _ was v, From the previous problem? Use the conservation oflinear momentum. Use SI units! / m W. /
la" —_ _.. 2P, t 2P4 ,, mitt. = tro+rvtjv _. m+rul If?! algal.“ (155 mfg“; I,» J
a ll : t '  . : 0. £6?) mfg ix"
reheat? _i_i}t'3__."li:f:l') l l / 1b] Through vvhat vertical height, h, does the center ol‘ gravityr oi“ the combined
system (m+l'vl}, projectile plus ballistic pendulum, rise after the projectile is
captured by the ballistic pendulum? Use the conservation of mechanical
energy. Ilse Si units! {KiU71 : t'r ratio; If I
lawwt: / U1: :1th a h : 3.} A i'ﬂﬁﬂﬂ kg railread bexear traveling te right at v; = Eﬂ mfg Strikes a aeeend
benear efunknewn mass. In; which is at rest. The}: stiek tegelher and metre
et‘Tte the right with a speed ef‘r” n = 5 ntfe. v' =2“ mfg Vg=ﬂmf5
l; r:  a
nil: Iﬂﬂﬂt} kg nh=? —: ﬁ'ig'J'L :0 3.3.} What is the unknewn mass {kg}. 1T1; , 0f the eeeend benear‘? Use l[.‘enaewatien
ef anentum. — Fi e = F ‘
{ii/WV. t :ﬁlth ii : {m I + ml) um J
. ' ' '— Il mlivl—nlﬂ'ifj)
. 'l 'l 1 I __ mil; . mlﬁll —'1 ml 2 ——_r
ﬂnlli‘ll I mkun ‘il— mLufl "'— T\l"1".1‘I"II'l ' l l I 1"”—
_. m; I) /
m ( lﬂrﬁbﬂ tq‘} HOW“?? 5 5 : Elma—gut?
1 2'. f
' 5 Mia 3.13] What is the initial tetai kinetie energy efthe twe eeXeare, eeFere eelliaien? / 2 M,
1: :Lrn‘u‘li' : J_ (triﬂJUC‘FH‘] (Emma) __ edemaTm J' N
i 1 l 3
: Z'jilil IiiI l 3.e} What is. the ﬁnal teta] kinetie energy erthe twe bexears, just after eellisien'? fr “'1 ‘ 2
I: = L [re +me Via} : i (leggemlce L geimiex 5"“ft)
‘5 ‘31 I ' l J
/ ,1
z 4g» : (mus 4.] Water strikes the turbine blades of a generator at a speed oi‘ VD = 15 [1'th so
that the rebounding Velocity of the water just after collision is 35% of its original speed it“ and is in eitaetijg,r the opposite direction just after collision. If the ﬂow rate, niassftime, is ﬁt} kgi’s, what is the average force, F, on the
turbine? Va: igﬂi'r‘rﬂ
26f
,_.."'_.'
/ Z?)
 :2) raw”)
or at Etsm) 5.] Four pcint masseei m = 3 kg, 1113: 3 kg, rm = 4 kg, and m4 = H] kg. are
lecateti at the ccerdinatee indicated belcw. Assume that this is a two
dimensional plane, and that the paint masses lie exactly an the grid points. 2” Calculate the cccrdinatea, in meters, of the center ct“ mass, rum = (xnn, ym. ),
Fer the above system of fear pcint masses. Use SI Unite! Note “cm” here
means “center 0f mass" NOT “centimeters”! rtﬁ1kq + mix; 4 mate 4 WT“
H___________________ '1' :
W rm 44ml +1113 + Tﬁut (3) 4 ELU“e)( i3  (Lawn; + maxi) mtg) L5+g+h+tﬂjpg
c +3t3+“0 _51m :I;:;:q m
W1L5L 4“ “WTLiz 4 mag; i ugh ...
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