Assignment2_MAT231 - -9% Section 2.3, #78. 1 - tan x = - (-...

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Assignment #2, Calculus I ( -36% total) -5% section 2.3, #52. The numerator is -x+3, which cancels yielding a -1, with the factor x - 3 in the denominator.
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-9% Section 2.3, #58. The quantity does not equal itself squared. Instead, you need to multiply numerator and denominator by (x+1)^1/2 + 2. -9% Section 2.3, #72. cos u tan u = cos u * (sin u / cos u) = sin u. Thus we have sin u / u, which tends to 1 as u tends to 0.
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Unformatted text preview: -9% Section 2.3, #78. 1 - tan x = - (- cos x + sin x)/ cos x. Divide by the denominator of the problem, and cancel (. ....), then put in the value for x.-4% Section 2.3, #108. Your t is correct (I'll call it t0). For part b, take the ratio the ratio ( s(t0) - s(t) )/ (t0 - t) = - (-16t^2 + 1000)/((t0 - t) = - (16t^2 - 1000)/(t - 7.9) = (factor the numerator and then cancel). .....
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This note was uploaded on 08/26/2008 for the course MATH MAT 231 taught by Professor Thurber during the Spring '08 term at Thomas Edison State.

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Assignment2_MAT231 - -9% Section 2.3, #78. 1 - tan x = - (-...

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