5
4
3
2
20
19
18
17
16
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
0
Bedrooms
Frequency
1
15
19
5
Histogram of Bedrooms
# Rooms Probability
2
0.125
3
0.475
4
0.375
5
0.025
Statistics I
Recitation Tuesday 2 – 3:15
Section 52
4,8,12,16,20,24
4. This reasoning is not correct. Getting 3 girls out of 5 births would imply that there is a 60%
chance of giving birth to a girl, which is not true. A better approach would be to state that the
probability of getting a girl would be 50%.
8. This table does not describe a probability distribution because the sum of the individual
probabilities is .977, which does not equal 1.
12. The study does not meet the criteria to describe a probability distribution. The sum of all the
individual probabilities is .9686, which is not equal to 1.
16.
a)
The mean of the sample probability distribution is
9.5980, given by the equation
∑[x
· P(x)] = μ
The range of usual outcomes is given by the inequality
9.5980  2
σ < X <
9.5980 + 2
σ
The standard deviation for the probability distribution is given by the formula
σ = √ ( ∑[x
2
· P(x)] – μ
2
) =
1.3901
9.598 – 2
σ = 6.8178
9.598 + 2
σ = 12.3782
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 Spring '08
 Hall
 Normal Distribution, Standard Deviation, Probability theory, Binomial probability

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