ch5 - Assignment 2 Questions from chapter 5 of McMurry and...

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Assignment 2. Questions from chapter 5 of McMurry and Fay Question numbers are from the fourth edition. Chapter 5. Periodicity and Atomic Structure 5.1 Gamma ray 8 _11 c 3.00 x m/s 10 = = 3.56 x m 10 ν λ = 8.43 x 10 18 s S 1 = 8.43 x 10 18 Hz Radar wave 8 _ 2 c 3.00 x m/s 10 = = 10.3 x m 10 ν λ = 2.91 x 10 9 s S 1 = 2.91 x 10 9 Hz 5.2 v = 102.5 MHz = 102.5 x 10 6 Hz = 102.5 x 10 6 s S 1 8 6 _1 c 3.00 x m / s 10 = = = 2.93 m 102.5 x 10 s λ ν v = 9.55 x 10 17 Hz = 9.55 x 10 17 s S 1 8 _10 17 _1 c 3.00 x m / s 10 = = = 3.14 x m 10 9.55 x 10 s λ ν 5.3 The wave with the shorter wavelength (b) has the higher frequency. The wave with the larger amplitude (b) represents the more intense beam of light. The wave with the shorter wavelength (b) represents blue light. The wave with the longer wavelength (a) represents red light. 5.4 Balmer series: m = 2; R = 1.097 x 10 S 2 nm S 1 2 2 1 1 1 = R _ m n λ ; 2 2 1 1 1 = R _ 7 2 λ ; 1 = λ 2.519 x 10 S 3 nm S 1 ; λ = 397.0 nm 5.5 Paschen series: m = 3; R = 1.097 x 10 S 2 nm S 1 2 2 1 1 1 = R _ m n λ ; 2 2 1 1 1 = R _ 3 4 λ ; 1 λ = 5.333 x 10 S 4 nm S 1 ; λ = 1875 nm 5.6 Paschen series: m = 3; R = 1.097 x 10 S 2 nm S 1 2 2 1 1 1 = R _ m n λ ; 2 2 1 1 1 = R _ 3 λ ; 1 λ = 1.219 x 10 S 3 nm S 1 ; λ = 820.4 nm 5.7 λ = 91.2 nm = 91.2 x 10 S 9 m 8 _9 c 3.00 x m/s 10 = = 91.2 x m 10 ν λ = 3.29 x 10 15 s S 1 E = hv = (6.626 x 10 S 34 J5s)(3.29 x 10 15 s S 1 ) = 2.18 x 10 S 18 J/photon E = (2.18 x 10 S 18 J/photon)(6.022 x 10 23 photons/mol) = 1.31 x 10 6 J/mol = 1310 kJ/mol 5.8 IR, λ = 1.55 x 10 S 6 m 8 _34 23 _6 c 3.00 x m / s 10 E = h = (6.626 x J s) (6.022 x / mol) 10 10 1.55 x m 10 λ E = 7.72 x 10 4 J/mol = 77.2 kJ/mol 103
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UV, λ = 250 nm = 250 x 10 S 9 m 8 _34 23 _9 c 3.00 x m / s 10 E = h = (6.626 x J s) (6.022 x / mol) 10 10 250 x m 10 λ E = 4.79 x 10 5 J/mol = 479 kJ/mol X ray, λ = 5.49 nm = 5.49 x 10 S 9 m 8 _34 23 _9 c 3.00 x m / s 10 E = h = (6.626 x J s) (6.022 x / mol) 10 10 5.49 x m 10 λ E = 2.18 x 10 7 J/mol = 2.18 x 10 4 kJ/mol 5.9 _34 _1 2 h 6.626 x kg 10 s m = = mv (1150 kg)(24.6 m/s) λ = 2.34 x 10 S 38 m 5.10 (Δx)(Δmv) h 4 5 π ; uncertainty in velocity = (45 m/s)(0.02) = 0.9 m/s _34 _1 2 _34 h 6.626 x kg 10 s m x = = 5 x m 10 4 ( mv) 4 (0.120 kg)(0.9 m/s) π ∆ π 5.11 n l m l Orbital No. of Orbitals 5 0 0 5s 1 1 S 1, 0, +1 5p 3 2 S 2, S 1, 0, +1, +2 5d 5 3 S 3, S 2, S 1, 0, +1, +2, +3 5f 7 4 S 4, S 3, S 2, S 1, 0, +1, +2, +3, +4 5g 9 There are 25 possible orbitals in the fifth shell. 5.12 (a) 2p (b) 4f (c) 3d 5.13 (a) 3s orbital: n = 3, l = 0, m l = 0 (b) 2p orbital: n = 2, l = 1, m l = S 1, 0, +1 (c) 4d orbital: n = 4, l = 2, m l = S 2, S 1, 0, +1, +2 5.14 The g orbitals have four nodal planes. 5.15 The figure represents a d orbital, n = 4 and l = 2. 5.16 m = 1, n = 5; R = 1.097 x 10 S 2 nm S 1 2 2 1 1 1 = R _ m n λ ; 2 2 1 1 1 = R _ 1 λ ; 1 1 = R 1 �� �� λ �� = 1.097 x 10 S 2 nm S 1 ; λ = 91.2 nm E = 8 _34 23 _9 3.00 x m/s 10 (6.626 x J s) (6.022 x / mol) 10 10 91.2 x m 10 E = 1.31 x 10 6 J/mol = 1.31 x 10 3 kJ/mol 5.17 (a) Ti, 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 2 or [Ar] 4s 2 3d 2 [Ar] 5 5 5 __ __ __ 104
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4s 3d (b) Zn, 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 or [Ar] 4s 2 3d 10 [Ar] 5 5 5 5 5 5 4s 3d (c) Sn, 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 2 4d 10 5p 2 or [Kr] 5s 2 4d 10 5p 2 [Kr] 5 5 5 5 5 5 5 5 5s 4d 5p (d) Pb, [Xe] 6s 2 4f 14 5d 10 6p 2 5.18 For Na + , 1s 2 2s 2 2p 6 ; for Cl S , 1s 2 2s 2 2p 6 3s 2 3p 6 5.19 The ground-state electron configuration contains 28 electrons. The atom is Ni.
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