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Soln to ch 11

Soln to ch 11 - Solutions to homework problems from chapter...

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Unformatted text preview: Solutions to homework problems from chapter 11 (BUAD2070) 2. s 2 = 25 a. With 19 degrees of freedom 2 .05 χ = 30.144 and 2 .95 χ = 10.117 2 19(25) 19(25) 30.144 10.117 σ ≤ ≤ 15.76 ≤ σ 2 ≤ 46.95 b. With 19 degrees of freedom 2 .025 χ = 32.852 and 2 .975 χ = 8.907 2 19(25) 19(25) 32.852 8.907 σ ≤ ≤ 14.46 ≤ σ 2 ≤ 53.33 c. 3.8 ≤ σ ≤ 7.3 6. a. 4.41 .2205 12 i x x n x = = = 2 2 ( ) 47.9500 1 i x x s n Σ- = =- 47.9500 6.92 s = = b. 2 .025 χ = 32.852 2 .975 χ = 8.907 2 (20 1)(47.95) (20 1)(47.95) 32.852 8.907 σ-- 27.73 ≤ σ 2 ≤ 102.28 5.27 ≤ σ ≤ 10.11 The 95% confidence interval for the population standard deviation ranges from a quarterly standard deviation of 5.27% to 10.11%. 15. a. Larger sample variance is 2 1 s 2 1 2 2 8.2 2.05 4 s F s = = = Degrees of freedom 20 and 25 Using F table, area in tail is between .025 and .05 Two-tail p-value is between .05 and .10 Exact p-value corresponding to F = 2.05 is .0904 p-value > .05, do not reject H ....
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Soln to ch 11 - Solutions to homework problems from chapter...

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