PHYS-102HW-01

PHYS-102HW-01 - PHYS-102 Summer-08 HOMEWORK-01 Outline of...

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PHYS-102 Summer-08 HOMEWORK-01 Outline of Solutions _____________________________________________________________ P19.8 Let the third bead have charge Q and be located distance x from the left end of the rod. This bead will experience a net force given by G F = k e 3 q () Q x 2 ˆ i + k e q Q d x 2 ˆ i ( ) . The net force will be zero if 3 x 2 = 1 d x 2 , or d x = x 3 . This gives an equilibrium position of the third bead of x = 0.634 d . The equilibrium is stable if the third bead has positive charge . P19.13 (a) G E 1 = k e q 1 r 1 2 ˆ j = 8.99 × 10 9 ( ) 3.00 × 10 9 ( ) 0.100 2 ˆ j =− 2.70 × 10 3 NC ˆ j G E 2 = k e q 2 r 2 2 ˆ i = 8.99 × 10 9 ( ) 6.00 × 10 9 ( ) 0.300 2 ˆ i 5.99 × 10 2 ˆ i G E = G E 2 + G E 1 5.99
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PHYS-102HW-01 - PHYS-102 Summer-08 HOMEWORK-01 Outline of...

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