PHYS-102HW-02SUM-08

PHYS-102HW-02SUM-08 - PHYS-102 Summer-08 HOMEWORK-02...

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PHYS-102 Summer-08 HOMEWORK-02 Outline of Solutions _____________________________________________________________ P19.30 The solution is straightforward: the electric flux is given by () ( ) θ Φ= = = × ° = G G 42 . cos 2.00 10 N C 18.0 m cos10.0 355 kN m C E EA EA 2 P19.38 (a) G E = 0 (why is the electric field zero inside the shell?) (b) E = k e Q r 2 = 8.99 × 10 9 32.0 × 10 6 ( ) 0.200 2 = 7.19 MN C G E = 7.19 MN C radially outward P19.55 F = k e q 1 q 2 r 2 : tan = 15.0 60.0 = 14.0 ° F 1 = 8.99 × 10 9 10.0 × 10 6 2 0.150 2 = 40.0 N F 3 = 8.99 × 10 9 10.0 × 10 6 2 0.600
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This note was uploaded on 09/03/2008 for the course PHYS 102 taught by Professor N/a during the Spring '08 term at Drexel.

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