# Web_Answers_8 - Z C = 1 · Z = X D = 1 Z = 1 E = X = X F =...

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Unit 8 Problem Solutions 8.1 8.2 (a) (contd) Static 1-hazards are: 1101↔1111 and 0100↔0101 8.2 (a) 15 V Z 0 5 10 20 25 30 35 40 t (ns) Y X W A B C D 00 01 11 10 00 01 11 10 1 1 1 1 1 1 1 1 F = A'C'D' + A C + B C'D A B C D 00 01 11 10 00 01 11 10 0 0 0 0 0 0 0 0 F = (A + C') (A'+ C + D ) (B + C + D') Static 0-hazards are: 0001↔0011 and 1000↔1001 8.2 (b) A B C D 00 01 11 10 00 01 11 10 1 1 1 1 1 1 1 1 F t = A'C'D' + A C + B C'D + A'BC' + ABD 8.2 (c) A B C D 00 01 11 10 00 01 11 10 0 0 0 0 0 0 0 0 F t = (A + C') (A' + C + D) (B + C + D') (A' + B + C) (A + B + D') 8.3 (a) 3 F G 1 2 4 5 6 7 t (ns) E C Glitch (static '1' hazard) A B C D 00 01 11 10 00 01 11 10 1 1 1 1 1 1 G = A'C'D + B C + A'BD Modifed circuit (to avoid hazards) 8.3 (b) A = 1; B =
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Unformatted text preview: Z ; C = 1 · Z = X ; D = 1 + Z = 1; E = X ' = X ; F = 1' = 0; G = X · 0 = 0; H = X + 0 = X See FLD Table 8-1, P. 214 8.4 A = B = 0, C = D = 1 So F = AB'D + BC'D' + BCD = But in the fgure, gate 4 outputs F = 1, indicating something is wrong. For the last NAND gate, F = 0 only when all its inputs are 1. But the output o± gate 3 is 0. There±ore, gate 4 is working properly, but gate 3 is connected incorrectly or is mal±unctioning. 8.5...
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