week 4 post lab

# week 4 post lab - Week 4 Freezing Point Depression Question...

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Week 4: Freezing Point Depression Question: How can you use the colligative property of freezing-point depression to experimentally determine the freezing constant of a solvent? Experimentally determine the K f of stearic acid. Compare literature value with percent error. Results Section: The question was to find the K f of stearic acid which was 2.0. This greatly differs from the theoretical result of 4.5. The experimental method we have used is we first combined of3.001 grams Lauric acid with 6.036 grams of stearic acid to explore colligative properties and obtain a freezing point. We then again took 6.036 (carefully measured again) grams of stearic acid and found it’s freezing point. The molality of the solution was then found and so was the difference in temperature. We plugged this into the equation to find the KF. Table 1. The Data and the Result (K f of stearic acid) Room Temperature of Solution 19.7 °C Grams of Stearic acid used 3.001g Grams of Lauric acid used 6.036 g Freezing Point of Stearic Acid 66 °C Freezing Point of solution (Lauric acid and Stearic acid) 57 °C Difference of the two temperatures (DT f ) 9 °C i ( van’t hoff factor): 1 M (molal concentration) 2.49 (mol/kg) K f: 3.6 Theoretical Yield 4.5 Percent Error 20 % Table 1. This table shows the data and the results of this lab. The actual result (which was to find the K f ) is underlined while the rest are data along with the percent error. The data includes the

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• Spring '07
• WINGRAVE
• Chemistry, Colligative properties, Freezing-point depression, stearic acid, 3.001g

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