# Chapter 26 - Chapter 26 39 Picture the Problem The image...

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Chapter 26 39. Picture the Problem : The image shows two light rays entering water. One ray enters at 10.0 ° and refracts to 8.00 ° . The second ray enters at 20.0 ° and refracts to 15.5 ° . Strategy: Solve Snell’s Law (equation 26-11) for the index of refraction of water using the given incident and refracted angles and the index of refraction for air (given in table 26-2). Then calculate the percent difference between the measured values and the index of refraction of water given in table 26-2. Solution: 1. Solve Snell’s Law for the index of refraction: 2. Calculate n w using : 3. Calculate the percent error: 4. Calculate the n w using : 5. Calculate the percent error: Insight: The refracted angles would have been 7.52 ° and 14.9 ° if Ptolemy had measured with perfect accuracy. 43. Picture the Problem : The figure shows a scuba diver who sees the sun at an angle of 35 ° from the vertical. The incident sunlight makes an angle of θ i with the vertical. Strategy: Use Snell’s Law (equation 26-11) to calculate the incident angle of the sunlight. The angle of the sun from the horizontal is Solution: 1. Calculate the incident angle: 2. Find the Sun’s angle above the horizon: Insight: The scuba diver perceives the Sun to be much higher in the sky than does his friend on the shore. 49. Picture the Problem : The image shows a light beam entering a 45 ° - 90 ° -45 ° prism perpendicular to the long side. It undergoes total internal reflection on both short sides before exiting vertically downward through the long side. Strategy: The angles of incidence for both internal reflections are exactly 45°. Solve equation 26-12 for the index of refraction for the prism, where the external index of refraction is that of air.

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Solution: Solve equation 26-12 for the minimum index of refraction: Insight:
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