STAT 415 - Homework 2 Solution

STAT 415 - Homework 2 Solution - Homework 2 Solution 5.3-4...

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Homework 2 Solution 5.3-4 a). 6.05 6.0171 6.05 ( 6.0171) ( ) ( 1.645) 0.05 0.02 0.02 X PX P PZ −− <= < = < = . b). Let Y be the number of boxes that weigh less than 6.0171. Then ~ (9,0.05) YB i n . So ( 2) 0.9916 PY ≤= from the table on page 678. c). ~ (6.05,0.004/9) XN . So 6.05 6.035 6.05 ( 6.035) ( ) ( 2.25) 1 0.9878 0.0122 0.02/ 3 0.02/3 X P = = −= 5.3-7 a). We know that ~ (8.78,0.16/ 9) and we cam draw the graphs of the pdf of both X and X based on their distribution. b).From page 283, we know that 2 2 2 (1 ) ~(1
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STAT 415 - Homework 2 Solution - Homework 2 Solution 5.3-4...

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