1169061032Xuj

1169061032Xuj - Alvarado, Patrick Homework 3 Due: Sep 28...

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Alvarado, Patrick – Homework 3 – Due: Sep 28 2006, 10:00 am – Inst: Andrei Sirenko 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. 001 (part 1 oF 3) 10 points A model airplane whose mass is 0 . 484 kg is tethered by a wire so that it ±ies in a circle 46 . 8 m in radius. The airplane engine provides a net thrust oF 0 . 751 N perpendicular to the tethering wire. ²ind the torque the net thrust produces about the center oF the circle. Correct answer: 35 . 1468 N · m. Explanation: Given : m = 0 . 484 kg , T = 0 . 751 N , and r = 46 . 8 m . The torque is τ = r T = (46 . 8 m) (0 . 751 N) = 35 . 1468 N · m . 002 (part 2 oF 3) 10 points ²ind the angular acceleration oF the airplane when it is in level ±ight. Correct answer: 0 . 033155 rad / s 2 . Explanation: The angular acceleration is α = τ I = τ m r 2 = 35 . 1468 N · m (0 . 484 kg) (46 . 8 m) 2 = 0 . 033155 rad / s 2 . 003 (part 3 oF 3) 10 points ²ind the linear acceleration oF the airplane tangent to its ±ight path. Correct answer: 1 . 55165 m / s 2 . Explanation: ²inally, the linear acceleration is: a = r α = (46 . 8 m) ( 0 . 033155 rad / s 2 ) = 1 . 55165 m / s 2 . keywords: 004 (part 1 oF 3) 10 points A 12 . 2 kg object is attached to a cord that is wrapped around a wheel oF radius 11 cm, as shown. The acceleration oF the object down the Frictionless incline is measured to be 2 . 13 m / s 2 . Assume the axle oF the wheel to be Frictionless. The acceleration oF gravity is 9 . 8 m / s 2 . 12 . 2 kg 13 m / s 35 11 cm Note: ²igure is not drawn to scale ²ind the tension in the rope. Correct answer: 42 . 5908 N. Explanation: Given : m = 12 . 2 kg a = 2 . 13 m / s 2 θ = 35 and g = 9 . 81 m / s 2 . T N mg a Parallel to the incline, F net = m a = m g sin θ - T T = m g sin θ - m a
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Alvarado, Patrick – Homework 3 – Due: Sep 28 2006, 10:00 am – Inst: Andrei Sirenko 2 = (12 . 2 kg)(9 . 8 m / s 2 ) sin 35 - (12 . 2 kg)(2 . 13 m / s 2 ) = 42 . 5908 N . 005
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This note was uploaded on 09/04/2008 for the course PHYS 106 taught by Professor Opyt during the Spring '08 term at NJIT.

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1169061032Xuj - Alvarado, Patrick Homework 3 Due: Sep 28...

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