hw5 - V A B B A A K 720.0 = + + = 1 1 2 V B V A B V B A V A...

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ME235 Thermodynamics I Section 002, Winter 2008 Homework #5 Solutions
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Sonntag and Borgnakke
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Sonntag and Borgnakke
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Sonntag and Borgnakke ) 300 287 . 0 /( 1 200 / 1 1 1 × × = = A A A A RT V P m = 2.323 kg ) 1000 287 . 0 /( 1 1000 / 1 1 1 × × = = B B B B RT V P m = 3.484 kg 0 and 0 2 1 2 1 = = W Q so the energy equation becomes 0 ) ( ) ( ) ( ) ( 1 2 0 1 2 0 1 2 1 2 1 2 = + = + = T T C m T T C m u u m u u m U U V B A
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Unformatted text preview: V A B B A A K 720.0 = + + = 1 1 2 V B V A B V B A V A C m C m T C m T C m T = = + = 2 / . 720 287 . 807 . 5 / ) ( tot 2 2 V RT m m P B A 600.0 kPa Sonntag and Borgnakke Sonntag and Borgnakke...
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This note was uploaded on 09/08/2008 for the course MECHENG 235 taught by Professor Pipe during the Spring '08 term at University of Michigan.

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hw5 - V A B B A A K 720.0 = + + = 1 1 2 V B V A B V B A V A...

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