PS10_Key

PS10_Key - 1. (Chapter 6 problem 4) Answer: Growth will be...

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1. (Chapter 6 problem 4) Answer: Growth will be supported by a particular compound if it is later in the pathway than the enzymatic step blocked in the mutant. Restated, the more mutants a compound supports, the later in the pathway it must be. In this example, compound G supports growth of all mutants and can be considered the end product of the pathway. Alternatively, compound E does not support the growth of any mutant and can be considered the starting substrate for the pathway. The data indicate the following: a. and b. A E C B D G 5 4 2 1 3 vertical lines indicate the step where each mutant is blocked c. A heterokaryon of double mutants 1, 3 and 2, 4 would grow as the first would supply functional 2 and 4, and the second would supply functional 1 and 3. A heterokaryon of the double mutants 1, 3 and 3, 4 would not grow as both are mutant for 3. A heterokaryon of the double mutants 1, 2 and 2, 4 and 1, 4 would grow as the first would supply functional 4, the second would supply functional 1, and the last would supply functional 2.
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2. (Chapter 6 problem 20) Answer: a. The first type of prototroph is due to reversion of the original ade1 mutant to wild type. The second type of prototroph is due to a new mutation (call it sup m ) in an unlinked gene that suppresses the ade1 phenotype. For the results of
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PS10_Key - 1. (Chapter 6 problem 4) Answer: Growth will be...

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