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Unformatted text preview: General Physics I General Physics I Durig Lewis Durig Lewis Example Example A car is traveling at a speed of 60 mph when the driver applies the brakes and decelerates at a rate of 10 mph/s. How long does it take the car to come to rest? Solution Solution v i = 60 mph x  axis a = 10 mph/s v a t = 60 10 / mph mph s t = 10 / 60 mph s t mph =  60 10 / mph t mph s = 6 t s = v f = 0 mph v = v f v i = 0 60 = 60 mph Example Example A car is traveling at a speed of 60 mph when the driver applies the brakes and decelerates at a rate of 10 mph/s. How far does the car travel before it comes to rest? Example Example x  axis Speed Time Distance Traveled = Speed Time Taken = Area under Graph Example Example Speed Time Distance Traveled = Area under Graph = Height Base = 60 mph 6 s 1 60 miles = 6 s 2 hour 1 60 1609 m = 6 s 2 3600 s =80.45 m =80.45 3.281f t =264 f t 1 mile = 1609 m 1 m = 3.281 ft 1 hour = 60 min. = 3600 s The Equations of Motion The Equations of Motion What do we care about knowing? Position (initial = x , final = x) Velocity (initial = v , final = v) Acceleration (a) Time (initial = 0, final = t) The Equations of Motion The Equations of Motion Change in Velocity Average Acceleration= Time Taken v a= t v  v a= t at = v  v v = v + at The Equations of Motion The Equations of Motion Speed Time Distance Traveled = Area Under Graph The Equations of Motion The Equations of Motion Speed Time v v  v t 1 2 t (v  v ) 1 2 = t at 2 1 2 = at = t v 2 1 2 Total Area= v t + at 2 1 2 Change in Position= v t + at 2 1 2 x  x = v t + at The Equations of Motion The Equations of Motion...
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 Spring '08
 Durig
 Physics

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