WEB Ideal Gas Law - Ideal Gas Law and the Molar Volume of a...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Ideal Gas Law and the Molar Volume of a Gas Basic Assumption: Gases at STP (273 K and 1 atm, 101.3 kPa or 760 mmHg) have a volume of 22.4 L How many moles of Helium are in 22.4 L? Step 1: 1 mole of gas occupies 22.4 L So, 22.4 L of Helium (or any gas) is 1 mole of gas 0.25 moles of Oxygen gas would have what volume? Step 1: 1 mole is 22.4 L (0.25 moles) x mole L 4 . 22 = 5.6 L 12 moles of CO 2 have what volume? Step 1: 1 mole is 22.4 L (12 moles) x mole L 4 . 22 = 268.8 L The basic equation we will be using in this unit is: PV=nRT P = Pressure in kPa or atm V = in liters n = the number of moles R = 8.31 K mole L kPa or 0.821 K mole L atm T = in Kelvin Alternatively we could write this equation as: PV=( MW grams )RT With this variant we can find the number of grams of a gas if we know the Molecular Weight
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Sample Problems: 1. How many moles of O 2 gas would fit in a 37.0 liter vessel at 60.00°C at a pressure of 3.50 atm? Step 1: Circle the variables and assign letters How many moles of O 2 gas would fit in a 37.0 liter vessel at 60.00°C at a pressure of 3.50 atm?
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern