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Unformatted text preview: volume (displaced oil) x rho (oil) = d.m (oil) = 2.111E-4 x 906 = 0.191 kg Buoyancy = d.m (oil) x gravity = 0.191 x 9.8 = 1.8718N Reading on spring = Weight (iron) - buoyancy = 1.66 x 9.8 - 1.8718 = 14.39N Question #11 Total weight in Newtons - Reading of Spring scale Question #12 V1 * D(wide)/D(small) = V2 Question #13 Question #14 V(c)=(2g(H2-H1))^(1/2) Question #15 P(atm)-PGH2 Question #16 b=P(atm)/PG - h2...
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This note was uploaded on 09/08/2008 for the course PHY 2048 taught by Professor Criss during the Spring '08 term at University of South Florida - Tampa.
- Spring '08