0168 00000631 u2 l gd h 3220139 from 6 136 aph

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Unformatted text preview: 1/ 3 2 P V A + (1 / M A ) + (1 / M B ) = 0.00143(355)1.75 1/ 2 1/ 3 2 V B 2 1/ 3 90.96 + 1115 . (1 / 78) + (1 / 92) Use the following additional properties and parameters, together with V = 0.0091 cP and V = u (7.84)(0.171) 0.171 lb/ft3 , where from Eq. (6-134), N ReV = V V = = 7,800 aV (28.1)(0.0091)(0.000672) (0.0091)(0.000672) From (6-135) NScV = V = = 0.639 V DV 0.052 (0.171) (2.54) 2 (12) 2 From Eq. (6-133), with CV = 0.408 from Table 6.8, (1) 1/ 3 2 = 0.052 cm2 / s 1 1/ 2 4 HG = ( - hL ) CV a4 1/ 2 (N ) (N ) -3/ 4 ReV ScV -1/ 3 uV a DV aPh -3/ 4 1 1/ 2 4(0.977) = ( 0.977 - 0.0273) 0.408 92.34 1/ 2 ( 7,800 ) ( 0.639 ) -1/ 3 (2.39)(92.3) = 0.23 m (0.052 10-4 )(144) At the top of the column, vapor rate = V =712 lbmol/h and liquid rate = L = 437 lbmol/h. Therefore, V/L = (712)/(437) = 1.63 At the bottom of the column: Near a mole fraction, xB , of 0.05, m = 2.1 Need an estimate of the liquid diffusivity of benzene in toluene at low concentrations of benzene. At the bottom, temperature = 227oF...
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This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .

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