# 1 031 from eq 6 97 the fractional liquid holdup is hl

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Unformatted text preview: nued) Liquid holdup based on conditions at the bottom of the column. By the continuity equation, superficial liquid velocity is, uL = LML /LS = (2570/3600)(18.1)/ [62.4(3.14)(DT)2/4] = 0.264/(DT)2 ft/s 2 0.264 / DT 62.4 90800 u L L From Eq. (6-98), N Re L = = = 2 L a (0.27)(0.000672)a DT a From Eq. (6-99), N FrL 2 2 u L a ( 0.264 / DT ) a a = = = 0.00216 4 g DT 32.2 2 Packing NOR PAC Montz DT, ft 3.4 4.2 uL, ft/s 0.0228 0.0150 a, ft2/ft3 26.5 91.4 N Re L 296 56.3 4.28 x 10-4 6.39 x 10-4 N FrL 0. 0 Since both values of N Re L are > 5, use Eq. (6-101), ah / a = 0.85Ch N Re25 N Fr.1 L L . For NOR PAC, ah / a = 0.85(0.651)(296) 0.25 (4.28 10 -4 ) 0.1 = 1057 For Montz, ah / a = 0.85(0.482)(56.3) 0.25 (6.39 10 -4 ) 0.1 = 0.54 From Eq. (6-97), the fractional liquid holdup is hL = 12 4.28 10 -4 For NOR PAC, hL = (12) 69.2 1/ 3 N FrL N Re L 1/ 3 ah a 2/3 (1.057 ) 2/3 = 0.0269 m3/m3 6.39 10 -4 2/3 For Montz, hL = (12) ( 0.54 ) = 0.0341 m3/m3 56.3 These liquid holdups at the bottom of the column are qu...
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## This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .

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