1 031 from eq 6 97 the fractional liquid holdup is hl

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: nued) Liquid holdup based on conditions at the bottom of the column. By the continuity equation, superficial liquid velocity is, uL = LML /LS = (2570/3600)(18.1)/ [62.4(3.14)(DT)2/4] = 0.264/(DT)2 ft/s 2 0.264 / DT 62.4 90800 u L L From Eq. (6-98), N Re L = = = 2 L a (0.27)(0.000672)a DT a From Eq. (6-99), N FrL 2 2 u L a ( 0.264 / DT ) a a = = = 0.00216 4 g DT 32.2 2 Packing NOR PAC Montz DT, ft 3.4 4.2 uL, ft/s 0.0228 0.0150 a, ft2/ft3 26.5 91.4 N Re L 296 56.3 4.28 x 10-4 6.39 x 10-4 N FrL 0. 0 Since both values of N Re L are > 5, use Eq. (6-101), ah / a = 0.85Ch N Re25 N Fr.1 L L . For NOR PAC, ah / a = 0.85(0.651)(296) 0.25 (4.28 10 -4 ) 0.1 = 1057 For Montz, ah / a = 0.85(0.482)(56.3) 0.25 (6.39 10 -4 ) 0.1 = 0.54 From Eq. (6-97), the fractional liquid holdup is hL = 12 4.28 10 -4 For NOR PAC, hL = (12) 69.2 1/ 3 N FrL N Re L 1/ 3 ah a 2/3 (1.057 ) 2/3 = 0.0269 m3/m3 6.39 10 -4 2/3 For Montz, hL = (12) ( 0.54 ) = 0.0341 m3/m3 56.3 These liquid holdups at the bottom of the column are qu...
View Full Document

This note was uploaded on 09/08/2008 for the course CHE 244 taught by Professor Selebi during the Spring '06 term at Lehigh University .

Ask a homework question - tutors are online