24 0002005 0002 496 from a rearrangement of eq

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Unformatted text preview: min = 1/ [( L / V ) - 1] = 1/(4.96 - 1) = 0.253. (c) The boilup ratio = VB = 1.2(0.253) = 0.3036. From Eq. (7-12), the slope of the stripping section operating line = L / V = (VB + 1)/VB = (0.3036 + 1)/0.3036 = 4.294. This line intersects the vertical q-line (xF = 0.05) at 0.002 + 4.294(0.05 - 0.002) = 0.2081. Therefore, the slope of the rectifying line = L/V = (0.35 - 0.2081)/(0.35 - 0.05) = 0.4730. From a rearrangement of Eq. (7-8), R = (L/V)/[1 - (L/V)] = 0.473/(1 - 0.473) = 0.8975. The equation for the rectifying section operating line, using Eq. ((7-9), with a modification for a partial condenser as determined from Fig. 7.18, is, y n +1 = R 1 xn + y D = 0.473xn + 0.184 5 R +1 R +1 (2) Analysis: (c) (continued) Exercise 7.22 (continued) The equation for the stripping section operating line, using Eq. (7-12) is, 1 V +1 y m +1 = B xm - x B = 4.294 xm - 0.00659 VB VB (3) We can now calculate stage by stage down from the top, starting from yD = 0.35, alternating between the equilibrium curve, Eq. (1) and the appropriate o...
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